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3 years ago

Hello can somebody help please

Mathematics

1 answer:

Basile [38]3 years ago

3 0

Answer:

C 170

Step-by-step explanation:

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Solve the equation for all real solutions in simplest form.<br> z^2 - 12z +9= -3

Mars2501 [29]

Answer:

Solving the equation for all real solutions in simplest form.

$z^2 - 12z +9= -3$ we get $\mathbf{z=10.9\: or\: z=1.1}$

Step-by-step explanation:

We need to solve the equation for all real solutions in simplest form.

$z^2 - 12z +9= -3$

First simplifying the equation:

$z^2 - 12z +9+3= -3+3\\z^2 - 12z +12= 0$

Now, we can solve the equation using quadratic formula:

$z=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

we have a = 1, b=-12 and c=12

Putting values in formula and finding values of x

$z=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\z=\frac{-(-12)\pm\sqrt{(-12)^2-4(1)(12)}}{2(1)}\\z=\frac{12\pm\sqrt{144-48}}{2}\\z=\frac{12\pm\sqrt{96}}{2}\\z=\frac{12\pm9.8}{2}\\z=\frac{12+9.8}{2}\:or\:z=\frac{12-9.8}{2}\\z=10.9\:or\:z=1.1$

So, we get value of z: z=10.9 or z=1.1

Solving the equation for all real solutions in simplest form.

$z^2 - 12z +9= -3$ we get $\mathbf{z=10.9\: or\: z=1.1}$

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Define the proper and improper subsets?

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Answer: A proper subset is one that contains few elements of the original set whereas an improper subset, contains every element of the original set along with the null set.

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Answer: $\frac{8}{15}$

Step-by-step explanation:

Let's re-write 3 as a fraction: $\frac{1}{3}$

Now all we have to do is multiply the numerator by the reciprocal of the denominator.

$\frac{8}{5}$ * $\frac{1}{3}$

$\frac{8}{5 *3}$

$\frac{8}{15}$

Your answer is: $\frac{8}{15}$

I hope this helps!

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