All categories

3 years ago

Solve 4-2×2+2/2-1=?a. 1b.0c.2d.4e. -1

Mathematics

2 answers:

Paul [167]3 years ago

7 0

Answer:

B.0

Step-by-step explanation:

4-2x2+2/2-1

4-4+1-1

0+0

Alexus [3.1K]3 years ago

6 0

Answer:

answer is 7

Step-by-step explanation:

well its not gonna be e and b for sure then u look closly u can get 4+2 that will be 6+2/2 then you get 7

You might be interested in

I can’t use my calculator so can someone please answer 2.8 quintillion to the power of 8 divided by 3.7 billion to the power of

sammy [17]

2.8 quintillion^8= 3.77802e+147
3.7 billion^12= 6.582952e+114

3.77802e+147/6.582952e+114=

=5.739097e+32

7 0

4 years ago

Help!! ________________

Tanya [424]

Answer:

NNNNNNNNNNNOOOOOOOOOOOOOOOOO i won't help you

Step-by-step explanation:

7 0

3 years ago

50 times what equals 10 million

kkurt [141]

Answer: 200,000

Explanation: divide 10,000,000 by 50 and it gives you the answer

7 0

3 years ago

Read 2 more answers

A group of 20 students attempting a mathematical challenge have an average age of 11.When their teacher is included their averag

miss Akunina [59]

Answer:

Teacher's age is 32.

Step-by-step explanation:

How you count the average age for people is:
(age of person 1 + age of person 2 ... ) / number of people = average age

Let's start by observing that we've got 2 equations coming from the text:

average of just students
20 students x 11 (average for a student) = sum of age of students
20 x 11 = 220
average of student and teacher
let's say x is age of teacher
together students & teacher is 20 + 1 = 21 people
(20 students x 11 + x)/ (20 + 1) = 12
(220 + x) / 21 = 12
220 + x = 12 * 21
x = 12 *21 - 220
x = 252 - 220
x = 32

hope this helps ❣️

7 0

1 year ago

It is estimated that t-weeks into a semester, the average amount of sleep a college math student gets per day S(t) decreases at

goldenfox [79]

Answer:

s(15)= $\frac{-3}{2} e^{15^{2} } +9.6$

Step-by-step explanation:

Before to getting started ,we have to consider the function which represents sleep decline rate S'(t) = $-3te^{t^{2} } \\$

Since this function is interpreted in this case as a rate of change, we can deduce this funcion is the first derivative of the function of average amount of sleep (S(t)).

In order to find S(t), we will integrate S'(t)

$\int\limits^ {} -3t3e^{t^{2} } \, dx \\$

This case corresponds to intergration by substitution

Substituting u= $x^{2} \\$

Computting the differential of u

$\frac{du}{dt} =2tdt\\$

Now, let's go back to our integral and write it in terms of u, using both definition of u and its defferential.

$\int\limits^{}-3te^{u} \, \frac{1}{2t}du \\\\\int\limits^{}\frac{-3}{2} e^{u}du\\$

The integral of a exponential function is itself. So the result is:

$\frac{-3}{2} e^{u} +c$

Now substitute u back in:

$\frac{-3}{2} e^{t^{2} } +c$

This answer correspond to function of average amount of sleep.

We know that when the semester begins (t=0) , math students sleep an average of 8.1 hours per day so we will use this info in order to find the value of c.

$s(0)=\frac{-3}{2} e^{0^{2} } +c=8.1\\\\\frac{-3}{2} +c=8.1$