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3 years ago

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A steel rod weighing 25 lb 11 oz is cut into three equal pieces. Find the weight of each piece of steel rod. Final answer must b

e expressed as such: ___ lb and ___ oz.

1 answer:

aleksandrvk [35]3 years ago

7 0

Answer:

200 AND 50

Step-by-step explanation:

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Simplify (2x^2+6x+5) - (6x^2+3x+5)

Sati [7]

Your answer will turn out to be −4x^2+3x.

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3 years ago

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Here is a list of ages (years) of children in a room: 5, 8, 5, 6, 8, 3, 6 State the median.

Ierofanga [76]

Answer:

6

Step-by-step explanation:

The median of a list of numbers is the number found in the "middle" of all the numbers. What this means is that it has the same amount of numbers larger and smaller than it in the list. To find the median, we first have to organize the list from least to greatest. Doing this, we get 3, 5, 5, 6, 6, 8, 8.

Now that we have the list, we can find the "middle number" by taking off numbers the highest number then the lowest number. Doing this we get

3, 5, 5, 6, 6, 8, 8

5, 5, 6, 6, 8

5, 6, 6

6

This means our median is 6.

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3 years ago

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There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In

Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

$\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}$

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

$P(0.45$

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

$z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)$

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

$P(p>0.8)=P(z>z^*)$

The z value is calculated as before:

$z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0$

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0

3 years ago

Describe the pattern in the sequence. Find the next two terms of the difference -2, -5,-8, -11

PSYCHO15rus [73]

Hello from MrBillDoesMath!

Answer:

"-3" is added to a sequence member to get the next number. This next two terms are -14 and -17

Discussion:

Note that -2 -3 = -5 and

-5 -3 = -8 and

-8 - 3 = -11

"-3" is added to a sequence member to get the next number. This implies that the next two terms are -11 -3 = -14 and -14 -3 = -17

Regards,

MrB

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3 years ago

Which pair of fractions shows a correct comparison? A.2/3 = 5/10 B.2/3 1/9 D.1/3 = 3/10 E.1/3 > 5/6 F.1/3 < 4/12

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