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Klio2033 [76]
2 years ago
7

Find the equation of the line that passes through both (5,1) and (8,-2)

Mathematics
1 answer:
Georgia [21]2 years ago
5 0

Let f(x) = ax+b be the line that passes through both points.

We know that f(5) = 1 and f(8) = -2. So:

\begin{cases}5a+b = 1 \\ 8a+b = -2\end{cases}

Solving the system, we get that a= -1 and b = 6.

So the line is equal to f(x) = 6-x.

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The points (1, 5) and (0, –2) fall on a particular line. What is its equation in slope-intercept form?
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The equation of the line in slope intercept form is y = 7x - 2

<h3>How to find the equation of a line?</h3>

The equation of the line can be solved with the following equation.

y = mx + b

where

  • m = slope
  • b = y-intercept

Therefore,

m = -2  - 5 / 0 - 1 = -7 / -1

m = 7

Hence, using (1, 5)

y = 7x + b

5 = 7(1) + b

5 - 7 = b

b = -2

Therefore,

y = 7x - 2

Hence, the equation of the line in slope intercept form is y = 7x - 2

learn more on equation of a line here: brainly.com/question/14956513

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