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Artyom0805 [142]
3 years ago
12

Permutation question pictured below :)

Mathematics
1 answer:
Dmitry [639]3 years ago
3 0

Answer:

(\frac{1}{5})(\frac{1}{4})(\frac{1}{3})

Step-by-step explanation:

First digit can be anything from 1 to 5 (5 numbers). <em>What is the probability of getting a "1" in the first digit? It is  \frac{1}{5}.</em>

<em />

Second digit can be anything from 2 to 5 (since 1 already in first digit place). <em>What is the probability of getting a "2" in the 2nd digit? It is  \frac{1}{4}</em>

<em />

Third digit can be anything from 3 to 5 (since 1 and 2 already in first and second digit, respectively). <em>What is the probability of getting a "3" in the 3rd digit? It is  \frac{1}{3}</em>.

The second answer choice is right.

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