What is the value of p in the equation
1 answer:
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Answer:
<em>Surface area of the roof of the kennel, including the bottom face is 58.96 ft^2</em>
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Step-by-step explanation:
The image is attached below
For the triangular sides of the roof, area is
A =
where b is the base = 4 ft
h is the vertical height = 2.24 ft
A = 4.48 ft^2
for the two faces we have 2 x 4.48 ft^2 = <em>8.96 ft^2</em>
For the rectangular sections of the roof, area is
A =
where is the length of the rectangle = 5 ft
h is the height of the rectangle = 3 ft
A = 5 x 3 = 15 ft^2
For the two rectangular faces, we have 2 x 15 ft^2 = <em>30 ft^2</em>
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For the bottom face, area is
A =
where is the length of the house = 5 ft
w is the width of the house = 4 ft
A = 5 x 4 = <em>20 ft^2</em>
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Surface area of the roof of the dog kennel is
<em>8.96 ft^2 + 30 ft^2 + 20 ft^2 = 58.96 ft^2</em>
Answer:
x=108
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
m∠RQS≅m∠QLK -----> by corresponding angles
m∠KLM+m∠QLK=180° -----> by supplementary angles (consecutive interior angles)
we have that
m∠RQS=x° ----> given problem
so
m∠QLX=x°
m∠KLM=(x-36)° ----> given problem
substitute
