Answer:
The answer is below
Step-by-step explanation:
a company decided to increase the size of the box for the packaging of their alcohol products. the length of the original packaging box was 40 cm longer than its width and the height 12 cm, volume was at most 4800 cm3. Suppose the length of the new packaging box is still 40cm longer than its width and the height is 12cm, what mathematical statement would represent the volume of the new packaging box?
Solution:
Let the width of the box be x cm.
The length of the box is 40 cm longer than the width, therefore the length of the box = x + 40
The height of the box = 12 cm
The volume of the box can be gotten from the formula:
Volume = length × width × height
Substituting:
Volume = (x + 40) × (x) × 12
Volume = 12x(x + 40)
Therefore the volume of the new box is 12x(x + 40)
Answer:
I'm pretty sure it's 4 sorry if I'm not right I'm not the best at this stuff either
A is correct:
Let volume v, length l, and h height.
v= (l²h)/3
v=(x²9)/3
v=3x²
Answer:
Not right.
Step-by-step explanation:
m <HGJ + m <KGJ =180°
So, m <HGJ = 180° - m <KGJ = 180° - 86° =94°
<span>v = 45 km/hr
u = 72 km/hr
Can't sketch the graph, but can describe it.
The Y-axis will be the distance. At the origin it will be 0, and at the highest point it will have the value of 120. The X-axis will be time in minutes. At the origin it will be 0 and at the rightmost point, it will be 160. The graph will consist of 3 line segments. They are
1. A segment from (0,0) to (80,60)
2. A segment from (80,60) to (110,60)
3. A segment from (110,60) to (160,120)
The motorist originally intended on driving for 2 2/3 hours to travel 120 km. So divide the distance by the time to get the original intended speed.
120 km / 8/3 = 120 km * 3/8 = 360/8 = 45 km/hr
After traveling for 80 minutes (half of the original time allowed), the motorist should be half of the way to the destination, or 120/2 = 60km. Let's verify that.
45 * 4/3 = 180/3 = 60 km.
So we have a good cross check that our initial speed was correct. v = 45 km/hr
Now having spent 30 minutes fixing the problem, out motorist now has 160-80-30 = 50 minutes available to travel 60 km. So let's divide the distance by time:
60 / 5/6 = 60 * 6/5 = 360/5 = 72 km/hr
So the 2nd leg of the trip was at a speed of 72 km/hr</span>
