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arsen [322]
3 years ago
9

WILL MARK BRAINLIEST, JUST HELP ME PLS

Mathematics
1 answer:
Luda [366]3 years ago
5 0

Answer:

SAS theorem

Step-by-step explanation:

If \frac{CE}{CB} = \frac{DC}{AC} and m∠ECD = m∠BCA, then the triangles are similar by the SAS theorem.

\frac{EC}{BC} =  \frac{14}{21} = \frac{2}{3}           \frac{DC}{AC} = \frac{18}{27} = \frac{2}{3}

So,  \frac{CE}{CB} = \frac{DC}{AC}  and m∠ECD = m∠BCA because vertical angles are congruent

Therefore ΔECD is similar to ΔBCA by SAS theorem

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babunello [35]
Let \mathbf V be the m\times3 matrix whose columns are \mathbf v_1,\mathbf v_2,\mathbf v_3, and let \mathbf c be the vector whose components are the constants c_1,c_2,c_3. Now consider the matrix equation

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PLZ HELP WUICK ILL MARK BRAINLEIST!!!
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Answer:

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