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3 years ago

Subtract. tenths tenths = tenths =

Mathematics

2 answers:

Step2247 [10]3 years ago

5 0

Answer: tenths?

Step-by-step explanation:

svp [43]3 years ago

5 0

Aşkım ne ben ben ben

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Answers: A.5 B.9 C.10 D.13 Need the answer ASAP

maw [93]

Answer:

x = 5

Step-by-step explanation:

See attached image.

8 0

2 years ago

Past records indicate that the probability of online retail orders that turn out to be fraudulent is 0.08. Suppose that, on a gi

Sunny_sXe [5.5K]

Answer:

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

Step-by-step explanation:

We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.

The probability of k online retail orders that turn out to be fraudulent in the sample is:

$P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{20}{k}\cdot0.08^k\cdot0.92^{20-k}$

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:

$P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483$

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

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4 years ago

Well this is the question. The Scoop website charges $29 for a four line classified ad. Each additional line costs $3.45. For an

ohaa [14]

Explanation:

The cost for the ad can be calculated as:

Cost = $29 + 3.45(3) + $20

Cost = $59.35

Because the ad has 7 lines, 4 that are include in the initial

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1 year ago

Find the square root of the following decimal numbers.

Softa [21]

Answer:

Answer is in picture

Step-by-step explanation:

Hope it is helpful.......

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3 years ago

Read 2 more answers

I will give u brainliest

Gre4nikov [31]

Answer:

rational

Step-by-step explanation:

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3 years ago

Subtract. tenths tenths = tenths =​

Subtract. tenths tenths = tenths =