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Aliun [14]
2 years ago
9

ONLY GIVING BRAINLYEST IF YOU ANSWER QUICKLY AND CORRECTLY

Mathematics
2 answers:
zhuklara [117]2 years ago
5 0

Answer:

hello can you follow me

Step-by-step explanation:

The correct answer is option B and D

k0ka [10]2 years ago
4 0

Answer:

B and D

Step-by-step explanation:

First, you have to solve the first equation. (Hint: you use the distributive property.)

2(5x + 2 + x)

10x + 4 + 2x

12x + 4

We can already see that B is correct and A is incorrect.

Now to solve C and D.

C = 2(5x + 3)

10x + 6

This is incorrect.

D = 2(6x + 2)

12x + 4

This is correct.

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The standard form of five and fiffty hundredths is
mash [69]

Answer:

You could do 5 x 1 = 5

And for fifty, 5 x 10 = 50

Step-by-step explanation:

Standard form is basically a big or small equation of the numbers

standard form is the usual way of writing numbers in decimal notation, i.e. standard form = 876, expanded form = 800 + 70 + 6, written form = eight hundred seventy six

Hope it helped :)

6 0
2 years ago
Yall please answer quickly, I will give brainliest!! Merry Christmas, Happy Hanukkah, and Happy Kwanzaa!
Schach [20]
23000 times 4=92000 hope This helps! Merry Christmas!
6 0
2 years ago
What is 2.5% of 15 530​
astraxan [27]

Answer:

2.5% of 15,530 is 388.25

4 0
2 years ago
Find the volume of the cylinder in terms of pi
jeyben [28]
The answer is 127.16 pi m³, hope this helps.
6 0
2 years ago
In an arithmetic sequence, t4 + t5 + t6 = 300, and t15 +t16+ t17 = 201. Find t18.
stiks02 [169]
In an arithmetic sequence:
Tn=t₁+(n-1)d

t₄=t₁+(4-1)d=t₁+3d
t₅=t₁+(5-1)d=t₁+4d
t₆=t₁+(6-1)d=t₁+5d

t₄+t₅+t₆=(t₁+3d) +(t₁+4d)+(t₁+5d)=3t₁+12d

Therefore:
3t₁+12d=300    (1)


t₁₅=t₁+(15-1)d=t₁+14d
t₁₆=t₁+(16-1)d=t₁+15d
t₁₇=t₁+(17-1)d=t₁+16d

t₁₅+t₁₆+t₁₇=(t₁+14d)+(t₁+15d)+(t₁+16d)=3t₁+45d

Therefore:
3t₁+45d=201    (2)

With the equations (1) and (2) we make an system of equations:

3t₁+12d=300
3t₁+45d=201

we can solve this system of equations by reduction method.

  3t₁+12d=300
-(3t₁+45d=201)
-----------------------------
       -33d=99      ⇒d=99/-33=-3

3t₁+12d=300
3t₁+12(-3)=300
3t₁-36=300
3t₁=300+36
3t₁=336
t₁=336/3
t₁=112

Threfore:

Tn=112+(n-1)(-3)
Tn=112-3n+3
Tn=115-3n

Now, we calculate T₁₈:

T₁₈=115-3(18)=115-54=61

Answer: T₁₈=61




5 0
3 years ago
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