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Aliun [14]
3 years ago
9

ONLY GIVING BRAINLYEST IF YOU ANSWER QUICKLY AND CORRECTLY

Mathematics
2 answers:
zhuklara [117]3 years ago
5 0

Answer:

hello can you follow me

Step-by-step explanation:

The correct answer is option B and D

k0ka [10]3 years ago
4 0

Answer:

B and D

Step-by-step explanation:

First, you have to solve the first equation. (Hint: you use the distributive property.)

2(5x + 2 + x)

10x + 4 + 2x

12x + 4

We can already see that B is correct and A is incorrect.

Now to solve C and D.

C = 2(5x + 3)

10x + 6

This is incorrect.

D = 2(6x + 2)

12x + 4

This is correct.

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Answer:

<em>( - 36, 24 ) </em>

Step-by-step explanation:

(- 9, 6) ------> ( - 9×4, 6×4) = <em>( - 36, 24 )</em>

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Ehich of thr following expressions has a Simplified value of 3A -2?
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Who has the greater slope?
Levart [38]

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They both have the same answer.

Step-by-step explanation:

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Which of these systems of equations shows the solution for the graph?
I am Lyosha [343]

Answer:

C)

Step-by-step explanation:

Note that one of the lines is simply y=-1 for any x, so we can dismiss the only answer without y=-1. That rejected answer is A)

Now let's notice, that the other line is decreasing y when increasing x. That tells us that in the equation y = ax + b, a has to be negative. This brings us to reject option D).

What is the y of that line for x = 0? Because y = ax + b, for x = 0 we will get the value of b. This is called the intercept. The line is at y=4 for x=0, so we know that the b in the equation must be positive 4. This fits answer C, but rejects answer B). And so, we have found that C) is the only possible answer.

4 0
3 years ago
Evaluate the definite integral using the graph of f(x)<br> (Image included)
Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20

Then by linearity, we have

\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}

8 0
2 years ago
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