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3 years ago

Help with set module 3 secondary math 3 3.3

Mathematics

1 answer:

sineoko [7]3 years ago

8 0

Answer/Step-by-step explanation:

7. (3x⁴ + 5x² - 1) + (2x³ + x)

Distribute +1 to each term in the parentheses by your right.

3x⁴ + 5x² - 1 + 2x³ + x

Rewrite in standard form

3x⁴ + 2x¾ + 5x² + x - 1

8. (4x² + 7x - 4) + (x² - 7x + 14)

Distribute +1 to each term in the parentheses by your right.

4x² + 7x - 4 + x² - 7x + 14

Collect like terms and add together

4x² + x² + 7x - 7x - 4 + 14

5x² + 10

9. (2x³ + 6x² - 5x) + (x⁵ + 3x² + 8x + 4)

2x³ + 6x² - 5x + x⁵ + 3x² + 8x + 4

Collect like terms and add together

2x³ + 6x² + 3x² - 5x + 8x + x⁵ + 4

2x³ + 9x² + 3x + x⁵ + 4

Rewrite in standard form

x⁵ + 2x³ + 9x² + 3x + 4

10. (-6x⁵ - 2x + 13) + (4x⁵ + 3x² + x - 9)

-6x⁵ - 2x + 13 + 4x⁵ + 3x² + x - 9

Collect like terms

-6x⁵ + 4x⁵ - 2x + x + 13 - 9 + 3x²

Add like terms

-2x⁵ - x + 4 + 3x²

Rewrite in standard form

-2x⁵ + 3x² - x + 4

11. (5x² + 7x + 2) - (3x² + 6x + 2)

Distribute -1 to each term in the parentheses by your right.

5x² + 7x + 2 - 3x² - 6x - 2

Collect like terms

5x² - 3x² + 7x - 6x + 2 - 2

2x² + x

12. (10x⁴ + 2x² + 1) - (3x⁴ + 3x + 11)

Distribute -1 to each term in the parentheses by your right.

10x⁴ + 2x² + 1 - 3x⁴ - 3x - 11

Collect like terms

10x⁴ - 3x⁴ + 2x² + 1 - 11 - 3x

7x⁴ + 2x² - 10 - 3x

Rewrite in standard form

7x⁴ + 2x² - 3x - 10

13. (7x³ - 3x + 7) - (4x² - 3x - 11)

Distribute -1 to each term in the parentheses by your right.

7x³ - 3x + 7 - 4x² + 3x + 11

Collect like terms

7x³ - 3x + 3x + 7 + 11 - 4x²

7x³ + 18 - 4x²

Rewrite in standard form

7x³ - 4x² + 18

14. (x⁴ - 1) - (x⁴ + 1)

Distribute -1 to each term in the parentheses by your right.

x⁴ - 1 - x⁴ - 1

Collect like terms

x⁴ - x⁴ - 1 - 1

-2

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The 80% confidence interval for difference between two means is (0.85, 1.55).

Step-by-step explanation:

The (1 - α) % confidence interval for difference between two means is:

$CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2,(n_{1}+n_{2}-2)}\times SE_{\bar x_{1}-\bar x_{2}}$

Given:

$\bar x_{1}=M_{1}=6.1\\\bar x_{2}=M_{2}=4.9\\SE_{\bar x_{1}-\bar x_{2}}=0.25$

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*Use a t-table for the critical value.

Compute the 80% confidence interval for difference between two means as follows:

$CI=(6.1-4.9)\pm 1.397\times 0.25\\=1.2\pm 0.34925\\=(0.85075, 1.54925)\\\approx(0.85, 1.55)$

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