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grandymaker [24]
2 years ago
8

We cannot hear echo in a small room, why ?​

Mathematics
1 answer:
Digiron [165]2 years ago
3 0

Answer:

yyyjhjjhmhjmhd

Step-by-step explanation:

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Help me solve this problem
dem82 [27]

Answer:

Step-by-step explanation:

y ÷ 3(4 - 2) + 5.5

= y ÷ 3(2) + 5.5

= y ÷ 6 + 5.5

= y/6 + 5.5

= (y + 33)/6

6 0
3 years ago
Which transformation will change figure a to figure b
vazorg [7]
It’s the first one.............
5 0
2 years ago
Read 2 more answers
A rectangle has an area of 8 square centimmetres and a perimeter of 12 cm. What are the width and breath?
vlada-n [284]
Let the Length be L and the Width be W

The area is 8 cm²
LW = 8

The perimeter is 12
2(L + W) = 12
L + W = 6

Solve L and W:
LW = 8 --------------- (1)
L + W = 6------------ (2)

Equation (2):
L + W = 6
L = 6 - W -------------- Sub into (1)
(6 - W) W = 8
6W - W² = 8
W² - 6W + 8 =0 
(W -2 )(W - 4) = 0
W = 2 or 4

When W =2, L = 6 - 2 = 4
When W = 4, L = 6 - 4 = 2

Answer: The Width is 2 cm and the Length is 4 cm
8 0
3 years ago
Find the value of x. What is the value of x?
Gre4nikov [31]

Answer:

x = 16

Step-by-step explanation:

The product of the lengths theorem is a property that can be sued to describe the relationships of the sides between the tangents and secants in a circle. One of these products states the following;

The distance between the point of tangency and its intersection point with the exterior secant squared is equal to the product of the exterior secant times the interior secant.

This essentially means the following equation can be formed;

(AB)^2=(DC)(CB)

Substitute,

12^2=x*9

Simplify,

144=9x

Inverse operations,

\frac{144}{9}=x\\\\16=x

6 0
3 years ago
Solve the following problem when -2 is outside an absolute value equation: -2|-2r-4|=-12
VMariaS [17]

-2|-2r-4|=-12

divide by -2

|-2r-4| = 6

we get a positive and negative solution

-2r-4 = 6     and -2r - 4 = -6

-add 4 to each side

-2r = 10         -2r = -2

divide by -2

r = -5    and r = 1


Answer r = -5 ,1


8 0
3 years ago
Read 2 more answers
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