Answer:
Ryo ordered
of the amount of eggs his restaurant needed
Step-by-step explanation:
Let's call z the number of eggs the restaurant needs
Ryo ordered 240% of the eggs he needed. Then Ryo ordered:
z.
This fraction can be simplified by dividing by 10 in the numerator and denominator.
Then it is:
![\frac{24}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B24%7D%7B10%7D)
It can be further simplified by dividing by 2 in the numerator and denominator:
z
Ryo ordered
of the amount of eggs his restaurant needed
Given:
Consider the given expression is:
![\dfrac{h+f}{3}+\dfrac{f+k}{2}+\dfrac{4h-k}{5}](https://tex.z-dn.net/?f=%5Cdfrac%7Bh%2Bf%7D%7B3%7D%2B%5Cdfrac%7Bf%2Bk%7D%7B2%7D%2B%5Cdfrac%7B4h-k%7D%7B5%7D)
To find:
The simplified form of the given expression.
Solution:
We have,
![\dfrac{h+f}{3}+\dfrac{f+k}{2}+\dfrac{4h-k}{5}](https://tex.z-dn.net/?f=%5Cdfrac%7Bh%2Bf%7D%7B3%7D%2B%5Cdfrac%7Bf%2Bk%7D%7B2%7D%2B%5Cdfrac%7B4h-k%7D%7B5%7D)
Taking LCM, we get
![=\dfrac{10(h+f)+15(f+k)+6(4h-k)}{30}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B10%28h%2Bf%29%2B15%28f%2Bk%29%2B6%284h-k%29%7D%7B30%7D)
![=\dfrac{10h+10f+15f+15k+24h-6k}{30}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B10h%2B10f%2B15f%2B15k%2B24h-6k%7D%7B30%7D)
![=\dfrac{34h+25f+9k}{30}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B34h%2B25f%2B9k%7D%7B30%7D)
Therefore, the required simplified fraction for the given expression is
.
The area of a regular polygon<span> is given by the formula which is expressed as:
</span>area = (½)(apothem<span>)(perimeter)
</span>
We calculate as follows:
area = (½)(7<span>)(7.2 x 5)
</span>area = 126 square units
Hope this answers the question.
Answer: 10
<u>Step-by-step explanation:</u>
varies directly means: ![\frac{y}{x} = k](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7Bx%7D%20%3D%20k)
Step 1: solve for k ⇒ ![\frac{21}{5} = k](https://tex.z-dn.net/?f=%5Cfrac%7B21%7D%7B5%7D%20%3D%20k)
Step 2: plug in the given value and k to solve for the missing value: ![\frac{42}{x} = \frac{21}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B42%7D%7Bx%7D%20%3D%20%5Cfrac%7B21%7D%7B5%7D)
42(5) = 21(x)
![\frac{42(5)}{21} = \frac{21(x)}{21}](https://tex.z-dn.net/?f=%5Cfrac%7B42%285%29%7D%7B21%7D%20%3D%20%5Cfrac%7B21%28x%29%7D%7B21%7D)
2(5) = x
10 = x