If the perimeter of a triangle is 19 cm. The lengths of 3 sides is: a = 8, b = 7, c = 4.
<h3>Parimeter</h3>
Let a = longest
Let b= shortest
Let c= third side
a = 2c
a = (b+ c) - 3
a + 3 = b + c
Using three variables to solve the expression for perimeter
Perimeter= 19 cm
a+ b + c = 19
a + (a + 3) = 19
2a + 3 = 19
2a= 16
Divide both side by 2a
a=16/2
a = 8
a = 2c
8 = 2c
c=8/2
c = 4
a + b + c= 19
8 + b + 4 = 19
12 + b = 19
b=19-12
b = 7
Hence,
a = 8, b = 7, c = 4
Therefore If the perimeter of a triangle is 19 cm. The lengths of 3 sides is: a = 8, b = 7, c = 4.
The complete question is:
Perimeter of triangle is 19cm. If the length of the longest side is twice that of the shortest side and 3 less than the sum of the lengths of the 2 sides find lengths of 3 sides.
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Answer:
287
Step-by-step explanation:
400+10=410
(70:100)*410
(70*410):100
28700:100 = 287
Answer:
BD = 28
Step-by-step explanation:
BC and CD are within line BD, so add those to make up for the length of BD
21 + 7 = 28
