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Amanda [17]
3 years ago
5

Which of the following triangles has a circle inscribed?

Mathematics
2 answers:
____ [38]3 years ago
5 0

Answer:

its your first option.

Step-by-step explanation:

Brainliest?

pychu [463]3 years ago
4 0

A circle is inscribed in the triangle if the triangle's three sides are all tangents to a circle. Since the triangle's three sides are all tangents to the inscribed circle, the distances from the circle's center to the three sides are all equal to the circle's radius.

Option A is the answer...

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Hi I am marriett and I need help on math homework <br>7e-4=31<br>e=___
blsea [12.9K]

Answer:

e= 5

Step-by-step explanation:

7e-4=31

7e= 31+4

7e= 35

e= 5

8 0
3 years ago
3b+4 = 25 <br> solve for b <br> no work needed
iris [78.8K]

Answer:

b = 7

I hope this helps!

3 0
3 years ago
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What is the distance between W(3, 1) and X(-2,-5)? Round to the nearest tenth.
Darina [25.2K]

Answer:

D. 7.8

Step-by-step explanation:

Distance formula: \sqrt{(x_{2} - x_{1})^2  +( y_{2} - y_{1})^2  }

Substituting          (-2 - 3)² + (-5 - 1)²

           Distance = \sqrt{(-5)^2 + (-6)^2}

Distance = \sqrt{25 + 36}

Distance = 7.8

5 0
3 years ago
Write your answer as a fraction in simplest form subtract 5/8-3/5
svetoff [14.1K]

first you need to find the least common denominator which in this case it is 40. since 5 and 8 both go into 40.


5/8 = 25/40

3/5 = 24/40

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4 0
3 years ago
Determine the margin of error for a 90% confidence interval to estimate the population mean when s = 40 for the sample sizes bel
Ann [662]

Answer:

a) The margin of error for a 90% confidence interval when n = 14 is 18.93.

b) The margin of error for a 90% confidence interval when n=28 is 12.88.

c) The margin of error for a 90% confidence interval when n = 45 is 10.02.

Step-by-step explanation:

The t-distribution is used to solve this question:

a) n = 14

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 14 - 1 = 13

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 13 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.7709

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.7709\frac{40}{\sqrt{14}} = 18.93

In which s is the standard deviation of the sample and n is the size of the sample.

The margin of error for a 90% confidence interval when n = 14 is 18.93.

b) n = 28

27 df, T = 1.7033

M = T\frac{s}{\sqrt{n}} = 1.7033\frac{40}{\sqrt{28}} = 12.88

The margin of error for a 90% confidence interval when n=28 is 12.88.

c) The margin of error for a 90% confidence interval when n = 45 is

44 df, T = 1.6802

M = T\frac{s}{\sqrt{n}} = 1.6802\frac{40}{\sqrt{45}} = 10.02

The margin of error for a 90% confidence interval when n = 45 is 10.02.

3 0
3 years ago
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