As you can see, I already answered part A. That part is easy, like kindergarten level. But I don't remember learning how to do p
art B, so if someone could explain it I would be very grateful.
2 answers:
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Answer:
- OT⊥BA;T is the midpoint of BA-------Given
- ∠BTO and ∠ATO are right angles ---Definition of perpendicular lines
- ∠BTO≅∠ATO---------------------------------All right angles are congruent
- T is the midpoint of BA------------------ Given
- TA≅TB-------------------------------------------Definition of midpoint
- TO≅TO------------------------------------------Reflexive
- ΔBOT≅ΔAOT---------------------------------SAS
Step-by-step explanation:
Given that ⊥
and
is the midpoint of
As ⊥
,
∠ and ∠
are right angles (Definition of perpendicular lines)
⇒∠≅ ∠
(All right angles are congruent)
T is the midpoint of (given)
⇒≅
(Definition of midpoint)
≅
(Reflexive)
Therefore, Δ≅Δ
(by SAS criteria ):
conditions:
- ∠
∠