Whats the answer to thos because its hard

Mathematics

1 answer:

storchak [24]3 years ago

6 0

To put a polynomial in standard form, combine all like terms and order the degrees of each term from highest to lowest, left to right.

since none of the terms are alike, move onto the degrees and variables.

$x^{2}$ + $3^{(1)}$ - $6x^{(1)}$ . the degrees are already in the correct order, but the variables are not. move the -6x before the 3, making the equation $x^{2}$ - 6x + 3, and it is in standard form.

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3 with tiny 2 on top+1•2

exis [7]

Answer:

Step-by-step explanation:

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'^' <em>is the exponent symbol</em>

7 0

4 years ago

Without a calculator determine if the whether sin 192 is postivte or a negatvive

Slav-nsk [51]

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4 years ago

According to this equation, what is the value of x at t=0? express your answer in terms of the variables a, b, m, and k.

andriy [413]

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5 0

4 years ago

I don't get how to do this so plz help me out and also click on the picture

Jlenok [28]

You have to distribute it or use FOIL (if u know that method). This is basically factoring.
for instance:
(2x-9)×(x+4)
first: 2x × x = 2x^2
second: 2x × 4 = 8x
third: -9 × x = -9x
forth: -9 × 4 = -36

now combine like terms.
2x^2 + 8x -9x - 36
(8x and -9x are like terms)
(add the two together, which is -1x or -x)
2x^2 -x -36 is ur answer

now do this same method for the rest

4 0

3 years ago

5. Find the sum of the first 35 terms of the arithmetic sequence when a = 5 and d = 4

Elza [17]

Answer:

The sum of the first 35 terms of the arithmetic sequence when a = 5 and d = 4 is 2555.

Step-by-step explanation:

Given:

a = 5

d = 4

To Find :

The sum of first 35 terms of the arithmetic sequence = ?