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Fed [463]
3 years ago
6

Joseph is creating a garden up against his fence in his backyard in the shape of a semi-circle. The diameter of his garden is 8

feet long. How much square footage of soil will he need to buy?
Plz help me I cant figure it out T_T
Mathematics
1 answer:
Marizza181 [45]3 years ago
7 0

Answer:

25 inches of soil

Step-by-step explanation:

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Please can you answer question b
alexira [117]

   198 + (199*3) + (200*2) +(201*5) + (202*2) = 2604

frequency = 1 + 3 +2 + 5 + 2 = 13

201 = (2604 + x )/14
multiply both sides by 14
x = 201*14 = 2604 +x

x = 2814 = 2604 +x

subtract 2604 from both sides:

x = 2814 - 2604
x = 210 cm

height of new player = 210 cm
3 0
3 years ago
|-24 + 12| lolololool
BaLLatris [955]
The answer to the equation is 12.
6 0
3 years ago
Read 2 more answers
I just need someone to answer these:
VladimirAG [237]

Answer:

7x4/8=3.5

9 × 7/10=6.3

(i dont know this one or the next, hope it helps! ❤

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Suppose the following number of defects has been found in successive samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6
Brut [27]

Answer:

Given the data in the question;

Samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.

a)

For a p chart ( control chart for fraction nonconforming), the center line and upper and lower control limits are;

UCL = p" + 3√[ (p"(1-P")) / n ]

CL = p"

LCL = p" - 3√[ (p"(1-P")) / n ]

here, p" is the average fraction defective

Now, with the 30 samples of size 100

p" =  [∑(6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.)] / [ 30 × 100 ]

p" = 234 / 3000

p" = 0.078

so the trial control limits for the fraction-defective control chart are;

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.078 + 3√[ (0.078(1-0.078)) / 100 ]

UCL = 0.078 + ( 3 × 0.026817 )

UCL = 0.078 + 0.080451

UCL = 0.1585

LCL = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.078 - 3√[ (0.078(1-0.078)) / 100 ]

LCL = 0.078 - ( 3 × 0.026817 )

LCL = 0.078 - 0.080451

LCL =  0 ( SET TO ZERO )

Diagram of the Chart uploaded below

b)

from the p chart for a) below, sample 28 violated the first western electric rule,

summary report from Minitab;

TEST 1. One point more than 3.00 standard deviations from the center line.

Test failed at points: 28

Hence, we conclude that the process is out of statistical control

Lets Assume that assignable causes can be found to eliminate out of control points.

Since 28 is out of control, we should eliminate this sample and recalculate the trial control limits for the P chart.

so

p" = 0.0745

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.0745 + 3√[ (0.0745(1-0.0745)) / 100 ]

UCL = 0.0745 + ( 3 × 0.026258 )

UCL = 0.0745 + 0.078774

UCL = 0.1532

LCL  = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.0745 - 3√[ (0.0745(1-0.0745)) / 100 ]

LCL = 0.0745 - ( 3 × 0.026258 )

LCL = 0.0745 - 0.078774

UCL = 0  ( SET TO ZERO )

The second p chart diagram is upload below;

NOTE; the red circle symbol on 28 denotes that the point is not used in computing the control limits

7 0
2 years ago
The table shows a cricket club's income in 2016 from a fete, a quiz and membership fees.
kirill [66]

Answer: 5:2:10

Income from fete = £250

13 x 5 + 35 = 100

25 x 20 = 500

250:100:500

Then simplify ratio -

25:10:50

5:2:10

8 0
3 years ago
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