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marshall27 [118]
3 years ago
13

A traffic officer is monitoring traffic on a windy section of road that has a speed limit of 55 miles per hour. A car speeds pas

t the officer and the radar gun indicates the car is traveling 68 miles per hour. How far will the speeding car travel in one minute?
Mathematics
1 answer:
Whitepunk [10]3 years ago
4 0

Answer:

The relative speed of the passing car is 13 miles per hour.

Step-by-step explanation:

v =  \frac{x}{t} \\  v = 13 \frac{mile}{hours}  \\ t = 1 \: min \:  =  \frac{1}{60}  \: hours \\ 13 =  \frac{x}{ \frac{1}{60} }  \\ 13 =  \frac{60 \: x}{1}  \\ x =  \frac{13}{60} miles \:  \\ and \: we \: are \: done.

i hope i have been useful buddy.

good luck ♥️♥️♥️♥️♥️.

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Your friend says that the absolute value equation |3x+8|−9=−5 has no solution because the constant on the right side of the equa
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Solution, solve\:for\:x,\:\left|3x+8\right|-9=-5\quad :\quad x=-4\quad \mathrm{or}\quad \:x=-\frac{4}{3}

Steps:

\left|3x+8\right|-9=-5

\mathrm{Add\:}9\mathrm{\:to\:both\:sides},\\\left|3x+8\right|-9+9=-5+9

\mathrm{Simplify},\\\left|3x+8\right|=4

|f\left(x\right)|=a\quad \Rightarrow \:f\left(x\right)=-a\quad \mathrm{or}\quad \:f\left(x\right)=a,\\3x+8=-4\quad \quad \mathrm{or}\quad \:\quad \:3x+8=4

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3x+8=4,\\\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides},\\3x+8-8=4-8,\\\mathrm{Simplify},\\3x=-4,\\\mathrm{Divide\:both\:sides\:by\:}3,\\\frac{3x}{3}=\frac{-4}{3},\\\mathrm{Simplify},\\x=-\frac{4}{3}

Combine\:the\:ranges,\\x=-4\quad \mathrm{or}\quad \:x=-\frac{4}{3}

\mathrm{The\:Correct\:Answer\:is\:No\:They\:Are\:Not\:Correct}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

4 0
3 years ago
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