The solution to given system of equations are (x, y) = (4, 2)
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
2x + 3y = 14 ---------- eqn 1
3x - 4y = 4 --------- eqn 2
We have to solve the given system of equations
We can solve the above system of equations by elimination method
<em><u>Multiply eqn 1 by 3</u></em>
3(2x + 3y = 14)
6x + 9y = 42 --------- eqn 3
<em><u>Multiply eqn 2 by 2</u></em>
2(3x - 4y = 4)
6x - 8y = 8 ----------- eqn 4
<em><u>Subtract eqn 4 from eqn 3</u></em>
6x + 9y = 42
6x - 8y = 8
( - ) --------------
9y + 8y = 42 - 8
17y = 34
<h3>y = 2</h3>
<em><u>Substitute y = 2 in eqn 1</u></em>
2x + 3(2) = 14
2x + 6 = 14
2x = 14 - 6
2x = 8
<h3>x = 4</h3>
Thus the solution to given system of equations are (x, y) = (4, 2)
Steps to solve:
15 + 2a = 35
~Subtract 15 to both sides
2a = 20
~Divide 2 to both sides
a = 10
Best of Luck!
The correct answer would be C. The variable
Answer:20
Step-by-step explanation:
Answer:
c=14•366
14•4 to the nearest tenth
Step-by-step explanation:
using Pythagoras theorem
c^2=a^2+b^2
c^2=7•9^2+12^2
c^2=62•41+144
c^2=206•41
take the square roots of both sides
c=14•3669
14•4 to the nearest tenth