Answer:
The answer to your question is: L = 30 ft
Step-by-step explanation:
Data
man = 6 ft
man shadow = 5 ft
lamppost shadow = 25 ft
lamppost height = ? = L
Process
![\frac{6}{5} = \frac{L}{25}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B5%7D%20%3D%20%5Cfrac%7BL%7D%7B25%7D)
![L = \frac{6 x 25}{5}](https://tex.z-dn.net/?f=L%20%3D%20%5Cfrac%7B6%20x%2025%7D%7B5%7D)
![L = \frac{150}{5}](https://tex.z-dn.net/?f=L%20%3D%20%5Cfrac%7B150%7D%7B5%7D)
L = 30 ft
Answer:
brainly.com
Step-by-step explanation:
sorry my bad copy paste error
Answer:
Step-by-step explanation:
Given are two functions represented one by graph and another by table
We can check the given statement one by one
1) ![f(2)=18 : f(0) =15](https://tex.z-dn.net/?f=f%282%29%3D18%20%3A%20f%280%29%20%3D15)
Average rate of change = ![\frac{18-15}{2-0} =1.5](https://tex.z-dn.net/?f=%5Cfrac%7B18-15%7D%7B2-0%7D%20%3D1.5)
For g(x) avg rate of change
=![\frac{g(2)-g(0)}{2-0} \\=4](https://tex.z-dn.net/?f=%5Cfrac%7Bg%282%29-g%280%29%7D%7B2-0%7D%20%5C%5C%3D4)
Hence g has a higher average rate of change than f.
True
2)f is linear and eventually exceeds g (f(0)>g(0) . True
3) True because y intercept is 10 for f while 8 for g
4) True because f(3) <g(3)
5) False both cannot be linear
15a^3b^4c^5----> answer B
you can only multiple like terms so
(5x3)= 15
now just add
a+a^2= a^3
b + b^3 = b^4
c^5 + 0= c^5