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Stells [14]
3 years ago
7

Find the area of rectangle with sides 2 5/6 and 4 4/7

Mathematics
2 answers:
Zanzabum3 years ago
6 0
Are of rectangle = length*wedth= 17/6* 32/7 = 544/42 cm^2
g100num [7]3 years ago
4 0
<h3><u>Given</u><u> </u><u>:</u></h3>

  • Length = \sf2\dfrac{5}{6} cm.
  • Breadth = \sf4\dfrac{4}{7} cm.

<h3><u>To</u><u> </u><u>Find</u><u> </u><u>:</u></h3>

The area of rectangle.

<h3><u>Solution</u><u> </u><u>:</u></h3>

Area of rectangle = Length × Breadth

\sf=2\dfrac{5}{6}\times4\dfrac{4}{7}

\sf=\dfrac{17}{6}\times\dfrac{25}{7}

\sf=\dfrac{17\times25}{6\times7}

\sf=\dfrac{425}{42}

<h3><u>Area</u><u> </u><u>of</u><u> </u><u>rectangle</u><u> </u><u>is</u><u> </u><u>4</u><u>2</u><u>5</u><u>/</u><u>4</u><u>2</u><u> </u><u>cm</u><u>²</u><u>.</u></h3>
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dalvyx [7]

Answer:

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Step-by-step explanation:

a) Given

x − y = 0  if  x = 0  ⇒  y = 0

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b) We make the change of variables as follows

u = x + y

v= x - y

If

x - y = 0  ⇒ v = 0

x − y = 2  ⇒ v = 2

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x + y = 3  ⇒ u = 3

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Answer:

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thus cos theta = adjacent/hypotenuse = \frac{\sqrt{7} }{4}

7 0
2 years ago
Read 2 more answers
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