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3 years ago

Draw counters in the ten-frame to show each number

Mathematics

1 answer:

Juliette [100K]3 years ago

4 0

first one is 1 the bottom is 10 2 in 20 3 in 30 4 in 40 5 in 50 6 in 60 7 in 70 8 in 80 9 in 90 then 100

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-1/13-10/39 in lowest terms

Ira Lisetskai [31]

Step-by-step explanation:

the answer is already as simplified as it could be

8 0

3 years ago

Shanna attends school for 1 week longer than 3/4 of the year. How many weeks in a year does Shanna attend school?

lorasvet [3.4K]

Answer:

48 weeks

Step-by-step explanation:

Theres 4 weeks in a month and times that by 12 and you get your answer, Hope this helps !

6 0

3 years ago

Read 2 more answers

Two samples each of size 25 are taken from independent populations assumed to be normally distributed with equal variances. the

NeTakaya

$n_1=25, n_2=25\\ \bar{X_1}=35.5, \bar{X_2}=33\\ s_1=3, s_2=4$

Pooled Combined Variance $s_p=12.5$

Test Statistic:

$t=\frac{\left(\bar{X_1}-\bar{X_2}\right)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

$t=\frac{\left(35.5-33\right)}{12.5\sqrt{\frac{1}{25}+\frac{1}{25}}}$

$\left|t\right|=0.01414$

Degrees of freedom = $n_1+n_2-2=25+25-2=48$

$\alpha =0.05$

$t-Critical =t_{\alpha /2, n_1+n_2-2}=t_{0.025, 48}=-2.0206 \\Table value=|t|=2.0206\\|t|=2.0206$

The table value is greater than the calculated value.

Thus we accept H0.

8 0

3 years ago

Simplify the expression to a polynomial in standard form: (4x+5) (x^2-3x-2) PLEASE HLEP

pickupchik [31]

Answer:

$4x^3-7x^2-23x-10$

Step-by-step explanation:

So we have the expression:

$(4x+5)(x^2-3x-2)$

Distribute. Multiply (4x+5) to each term:

$(x^2)(4x+5)+(-3x)(4x+5)+(-2)(4x+5)$

Distribute:

$=(4x^3+5x^2)+(-12x^2-15x)+(-8x-10)$

Combine like terms:

$=(4x^3)+(5x^2-12x^2)+(-15x-8x)+(-10)$

Add and simplify:

$=4x^3-7x^2-23x-10$

And this is in descending order, so it's in standard form.

7 0

3 years ago

Help plz I will make u a barinllest

irakobra [83]

A I believe a is correct

6 0

3 years ago