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Alexxandr [17]
3 years ago
10

Ally ran 5 miles in 6 minutes. Sami ran 6 mile. If ally ran at a faster rate than Sami ,in how many minutes could Sami have run

6 miles
Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
8 0
Answer:6 minutes
(not really sure that is what i got)
Yuri [45]3 years ago
5 0
So you need to set up something called a proportion. You should know what that is. With the ratio(fraction) 5-out-of-6, followed by an equal sign(=), and then the fraction(read carefully!) 6-out-of-n. N is your denominator. Now perform Means and Extremes, or cross multiplying. Multiply 5*n to get 5n. Multiply 6*6 to get 36. Now you need to isolate the variable from 5. Divide 5n to get 'n', and divide 36/5 to get 7.5. You end up with n=7.5. The value of n is 7.5, and that is your answer. To check, replace n with 7.5 in the proportion. Cross multiply to get the two numbers. If equivalent, then congrats, you have the right answer!
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a) The 99% confidence interval would be given by (5004.168;12603.832)

b) For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X =9004 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=5629 represent the sample standard deviation

n=20 represent the sample size  

2) Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=20-1=19

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,19)".And we see that t_{\alpha/2}=2.86

Now we have everything in order to replace into formula (1):

9004-2.86\frac{5629}{\sqrt{20}}=5004.168    

9004+2.86\frac{5629}{\sqrt{20}}=12603.832

So on this case the 99% confidence interval would be given by (5004.168;12603.832)    

3) Part b

For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

7 0
3 years ago
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