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3 years ago

B is between A and C, AC = 14 and BC = 11.4. Find AB

Mathematics

1 answer:

djverab [1.8K]3 years ago

8 0

Answer: 2.6

Step-by-step explanation:

1. We know that A to C is 14

2. B to C is 11.4 so we're going to find the remainder to equal 14.

3. 14 minus11.4 which equals 2.6

4. AB is 2.6

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Find a particular solution to y" - y + y = 2 sin(3x)

leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

$\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x$

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

$=e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}$

Multiplying both sides of equation (1) by integrating factor and integrating we get

$\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I$

$I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx$

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2 years ago

What numbers add to 10 and multiply to negative 144?

Ilya [14]

The answers would be -8 and 18

-8×18 = -144
-8+18 = 18-8 = 10

4 0

3 years ago

Joshua used two wood beams, PC and QA, to support the roof of a model house. The beams intersect each other to form two similar

Sliva [168]

PR : RC = PQ : AC

so,

PQ = 2.8 inches

Hope this helps

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3 years ago

Read 2 more answers

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konstantin123 [22]

Answer:

O The range of the function is all real numbers greater

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Step-by-step explanation:

The function f(x) = -square root x is shown on the graph.

Which statement is correct?

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The domain of the function is all real numbers less

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O The range of the function is all real numbers greater

than or equal to 0.

The range of the function is all real numbers less

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The domain of the function is all real numbers less

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3 years ago

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Help I need to know plz

lana66690 [7]

Answer:

4 quarts

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3 years ago