It does not contain an equal sign. It cannot be solved for unless the value of the variable is given.
All you have to do is plug in.
x = 1 , y= 8
3x+5=y
3(1) + 5 = 8
3+5 = 8
8=8
They are both equal, yes. The coordinates work out in the equation. Both sides are equal so the coordinates work. The answer is yes.
To put an equation into (x+c)^2, we need to see if the trinomial is a perfect square.
General form of a trinomial: ax^2+bx+c
If c is a perfect square, for example (1)^2=1, 2^2=4, that's a good indicator that it's a perfect square trinomial.
Here, it is, because 1 is a perfect square.
To ensure that it's a perfect square trinomial, let's look at b, which in this case is 2.
It has to be double what c is.
2 is the double of 1, therefore this is a perfect square trinomial.
Knowing this, we can easily put it into the form (x+c)^2.
And the answer is: (x+1)^2.
To do it the long way:
x^2+2x+1
Find 2 numbers that add to 2 and multiply to 1.
They are both 1.
x^2+x+x+1
x(x+1)+1(x+1)
Gather like terms
(x+1)(x+1)
or (x+1)^2.
Answer:
The linear term is -5x
Step-by-step explanation:
The linear term is the term that has the degree equal to 1.
The given function is
y = 2x^2 − 5x − 12
here 2x^2 = quadratic term i.e having degree 2
-5x = linear term i.e having degree 1
-12 = constant
so, The linear term is -5x
Answer:
5
Step-by-step explanation:
