Newton has 28 cows Sally has 17 what is the sum?
2 answers:
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Answer:
○ 3
○ y + ½ = 3(x - 2)
○ Multiply both sides of the equation by 3. The Standard Form of the equation is 12x - 2y = 24.
○ 5x - 3y = 15
○ y = ½x + 5⁄2
Step-by-step explanation:
Find the <em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>]:
-y₁ + y₂\-x₁ + x₂ = m → (-1, 1) and (-2, -2)
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According to the Point-Slope Formula, <em>y - y₁ = m(x - x₁)</em>, all the negative symbols give the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL inserting this coordinate into the formula with their CORRECT SIGNS:
(2, -½) → y + ½ = 3(x - 2)
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We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it:
-3[4x - ⅔y = 8] → -12x + 2y = -24
** They should have multiplied by -3 instead of 3 because that negative is hooked up to everything in the fraction, but since the exercise gave you 12x - 2y = 24, go with 12x - 2y = 24.
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If you would take a look at this graph real closely, you will see that this graph intersects the y-axis and x-axis at ENDPOINTS, so to find the x-intercept, you simply plug in <em>zero</em> for <em>y</em>: 5x = 15, and you will know right away that <em>x</em><em> </em>is set to equal 3, which is what you see in the graph, (3, 0). Now, to find the y-intercept, you simply plug in <em>zero</em><em> </em>for <em>x</em>: -3y = 15, and you will know right away that <em>y</em><em> </em>is set to equal -5, which is what you see on the graph as well, (0, -5). With that being said, you have your answer.
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y - 3 = ½(x - 1)
y - 3 = ½x - ½
+ 3 + 3
_____________
y = ½x + 2½
* 2½ = 5⁄2
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Part A: The solution is
Part B: The point is not in the solution set.
Explanation:
Part A: The given inequalities are and
The solution can be determined by solving the two inequalities by substitution method.
Changing inequalities to equality, we have,
and
Let us substitute in the equation
, we get,
Substituting in
, we get,
Thus, the solution set is
Part B: Now, we shall determine whether the point is in the solution set.
Let us substitute the point in the inequalities
and
, we get,
Also, substituting in
, we get,
Since, the point does not satisfy one of the inequality
, the solution set does not contain the point
Thus, the point is not in the solution set.