Okay let's see.. 0.750
1.200
As we see 1 is bigger than 0.So that means 1/2 is bigger.Hope this helps! (;
Answer:
"To the nearest year, it would be about 9 years"
Step-by-step explanation:
11c)
This is compound growth problem. It goes by the formula:

Where
F is the future amount
P is the present (initial) amount
r is the rate of growth, in decimal
t is the time in years
Given,
P = 20,000
r = 8% = 8/100 = 0.08
F = double of initial amount = 2 * 20,000 = 40,000
We need to find t:

To solve exponentials, we can take Natural Log (Ln) of both sides:

Using the rule shown below we can simplify and solve:

We can write:

To the nearest year, that would be about 9 years
Given:
October: 8 3/8 inches
September : 60% less rain fell than in October.
This means that only 40% rain fell in September based on the amount of rain that fell in October.
8 3/8 ⇒ (8*8)+3/8 = 67/8
40% is 4/10
67/8 * 4/10 = 268/80 = 3 28/80 or 3 7/20 or 3.35
28 ÷ 2 = 14
80 ÷ 2 = 40
14 ÷ 2 = 7
40 ÷ 2 = 20
In September 3 7/20 inches or 3.35 inches of rain fell.
Answer:
71°
Step-by-step explanation:
The triangle shown is an isosceles triangle. Isosceles triangles have two equal sides and two equal angles. When all 3 angles are added, it should have a sum of 180°. The tip of the triangle is the part of the triangle with the smallest degree/angle. So the two remaining angles are the same amount.
180°=38°+x+?
180°=38°+71°+71°
Both missing angles are the same degree, and when both are added to 38, it has a sum of 180. x is equal to 71°.
Answer:
(a): <u>x</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>ky</u><u> </u><u>is</u><u> </u><u>-</u><u>1</u>
<u>(</u><u>b</u><u>)</u><u>:</u><u> </u><u>k</u><u> </u><u>is</u><u> </u><u>-</u><u>2</u>
Step-by-step explanation:
Let: 3x + ky = 8 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em>
x - 2 ky = 5 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em>
<em> </em>Then multiply <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em><em> </em>by 2:
→ 6x + 2ky = 16, let it be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em>
Then <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em><em> </em><em>+</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em><em>:</em>
<em>
</em>
<em>T</em><em>h</em><em>e</em><em>n</em><em> </em><em>k</em><em>y</em><em> </em><em>:</em>

