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3 years ago

HELP THIS IS MY SECOND ATTEMPT

Mathematics

1 answer:

Colt1911 [192]3 years ago

6 0

More than half received below a 90.

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Half the sum of seven and w?

swat32

Answer:

3.5w

Step-by-step explanation:

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3 years ago

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Find the difference.<br><br> (4−5y)−2(3.5y−8)

MAVERICK [17]

Answer:

-12y + 20

Step-by-step explanation:

First, you simplify each term:

apply the distributive property:

4 - 5y - 2 (3.5y) - 2 x -8

Multiply 3.5 by -2:

4 - 5y - 2 (3.5y) - 2 x -8

Multiply -2 by -8:

4 - 5y - 7y +16

Next, we simplify by adding terms:

Add 4 + 16:

-5y - 7y + 20

Subtract 7y from 5y:

-12y + 20

Hence the simplified form is -12y + 20

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2 years ago

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find the midpoint of the line segment whose endpoints are (-2, 5) and (4, -9). (2, -7) (1, -4) (1, -2)

Alex_Xolod [135]

M(x, y) = ((x1 + x2)/2, (y1 + y2)/2) = ((-2 + 4)/2, (5 - 9)/2) = (2/2, -4/2) = (1, -2)

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3 years ago

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Question 15

borishaifa [10]

A is the answer I think

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3 years ago

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A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimat

Contact [7]

Answer: a. n= 1068

b. n= 164

Step-by-step explanation:

The formula to find the sample size :

$n=p(1-p)(\dfrac{z^{*}}{E})^2$

, where p=prior population proportion , z* = critical z-value and E = Margin of error.

Here , let p=proportion of computers that use a new operating system.

Given : Confidence level = 95%

i.e. z* = 1.96 [by z-table]

Margin of error : E = 3% =0.03

a. If p is unknown , then we assume p=0.5

Then, $n=(0.5)(1-0.5)(\dfrac{1.96}{0.03})^2=1067.11111\approx1068$

i.e. n= 1068

b. p=0.96

Then, $n=(0.96)(1-0.96)(\dfrac{1.96}{0.03})^2=163.908266667\approx164$

i.e. n= 164.

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3 years ago