Question

What is the phase shift of y = –csc(3x − π)?

Answer 1

Answer:

$\frac{\pi}{3}$

Step-by-step explanation:

We are asked to find the phase shift of the function $y=-\text{csc}(3x-\pi)$.

We know that a function of form $f(x)=a\cdot \text{csc}(bx-c)+d$, where,

$\text{Period}=\frac{2\pi}{|b|}$,

$\text{Phase shift}=\frac{c}{b}$,

$\text{Vertical shift}=d$

Upon comparing our given function with standard function we can see that $a=-1$, $b=3$ and $c=\pi$.

$\text{Phase shift}=\frac{\pi}{3}$

Therefore, the phase shift for our given function is $\frac{\pi}{3}$.

Answer 2

The answer is pie over three