Question

Using the quadratic formula to solve x2 = 5-x, what are the values of x?

Answer 1

Answer:

A) (-1 ± √21)/ 2

Step-by-step explanation:

Move all terms onto one side

          $x^{2}$ = 5-x

$x^{2}$ + x - 5 = 0

Insert values into quadratic formula

a = 1      b= 1     c= - 5

[-b ± √($b^{2}$ - 4ac)]/2a

[-1 ± √($1^{2}$ - 4 (1(-5)]/ 2(1)

(-1 ± √21)/ 2

Answer 2

Answer:

its the first choice, negative 1 plus or minus square root of 21 over 2

Step-by-step explanation: