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Natalija [7]
3 years ago
15

Evaluate f(x)= -6+12 when x= -3,x=0, and x=1.

Mathematics
1 answer:
Anton [14]3 years ago
5 0

Given :

A function, f(x) = -6 + 12

To Find :

The value of f(x) when x= -3, x= 0 and x=1.

Solution :

Given function is f(x) = -6 + 12 .

Simplifying above function, we get :

f(x) = 6

Now, the given function is independent of x.

So, for any value of x the the value of functions remains constant.

Hence, this is the required solution.

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Without using calculator or table find the value of sin 15°​
lubasha [3.4K]

Answer:

.25881

Step-by-step explanation:

sin15

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=sin45.cos30-cos45.sin30

=(0.707×0.86)-(0.707×0.5)

=(0.6082)-(0.3535)

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6 0
3 years ago
Simplify the expression.<br>13[6^2/(5^2-4^2)+9]<br><br> 181<br><br> 169<br><br> 26<br><br> 585
Zina [86]
So 5^2 -4^2 is 25-16 which is 9
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7 0
2 years ago
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yuradex [85]
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Hope that this helps!
8 0
3 years ago
Let f(x) =x+1 and g(x)=1/x. The graph of (f o g)(x) is shown below. What is the range of (f o g)(x)?
sveta [45]
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6 0
3 years ago
Read 2 more answers
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sveta [45]
The value of x is 13 for the first attachment. 
5 0
2 years ago
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