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Natalija [7]
3 years ago
15

Evaluate f(x)= -6+12 when x= -3,x=0, and x=1.

Mathematics
1 answer:
Anton [14]3 years ago
5 0

Given :

A function, f(x) = -6 + 12

To Find :

The value of f(x) when x= -3, x= 0 and x=1.

Solution :

Given function is f(x) = -6 + 12 .

Simplifying above function, we get :

f(x) = 6

Now, the given function is independent of x.

So, for any value of x the the value of functions remains constant.

Hence, this is the required solution.

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(Calculus help, 25 points, will give brainliest) Find the sum of the sigma notation below.
Andreyy89

\displaystyle\sum_{i=3}^{10}(2i-9)=2\sum_{i=3}^{10}i-9\sum_{i=3}^{10}1

Recall that

\displaystyle\sum_{i=1}^n1=n

\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2

Your sums start at i=3, so in order to apply these formulas directly, you need to compensate for the missing first two terms:

\displaystyle\sum_{i=3}^{10}1=\sum_{i=1}^{10}1-(1+1)=10-2=8

\displaystyle\sum_{i=3}^{10}i=\sum_{i=1}^{10}i-(1+2)=\frac{10\cdot11}2-3=52

\implies\displaystyle\sum_{i=3}^{10}(2i-9)=2\cdot52-9\cdot8=\boxed{32}

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