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Gwar [14]
3 years ago
12

What are the factors of 96?

Mathematics
1 answer:
lbvjy [14]3 years ago
4 0

Answer: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48,

Step-by-step explanation: These are all the factors for 96.

Hope this helps !

I am joyous to assist you anytime.

^^

~Jarvis

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I need help please!!!
myrzilka [38]

the slope of the given point is m=−3/4

5 0
1 year ago
Find the exact value of each trigonometric function for the given angle θ.
irina [24]

Answer:

[rad] 2.41

Step-by-step explanation:

Since it gave you the point and the angle to find, you simply just have to solve for the inverse of cot. Remember cot is the opposite of tan, so cot is cos/sin. In that case, we plug into the calc (in radians):

cot^-1(-√5/2)

And we should get 2.41 as our answer!

3 0
3 years ago
Please help I’ll mark brainliest if correct please explain also
adell [148]

Answer:

2/5

Step-by-step explanation:

5x+6y=11

as we have to find x coordinate

while y coordinate 3/2 is already given in question

so only put value of y coordinate in given equation to get x coordinate value

5x+6y=11

5x+6*(3/2)=11

5x+3*3=11

5x+9=11

5x=11-9

5x=2

x=2/5

6 0
3 years ago
In the number 3,335 how many times greater is the value of the 3 on the left than the 3 on the right
AlekseyPX

Answer:

(If they were talking about 3,335, then) 100 times greater

(If they were talking about 3,335 then) 10 times greater

Step-by-step explanation:

When you visualize it, ignore the other numbers and think of only the threes.

Count how many spaces/places they are from each other, and that's how many 0s you should put after a 1 as your answer.

Same as decimal moving and multiplying by 10's.

8 0
3 years ago
Bacteria of species A and species B are kept in a single environment, where they are fed two nutrients. Each day the environment
DiKsa [7]

Answer:

We require 4,550 of species A and 1,460 of species B that can coexist in the environment so that all the nutrients are consumed each day

Step-by-step explanation:

Let n₁ be the population of A required and n₂ be the population of B required.

Now we require 2 units of the first nutrient for species A and one unit of the first nutrient for species B. The total nutrients required by species A is 2n₁ and that by species B is 1n₂ = n₂. So, the total nutrients required by both species A and B is 2n₁ + n₂. Since this equals the quantity of the first nutrient which is 10,560, then  2n₁ + n₂ = 10,560 (1)

Now we require 5 units of the second nutrient for species A and 6 units of the second nutrient for species B. The total nutrients required by species A is 5n₁ and that by species B is 6n₂. So, the total nutrients required by both species A and B is 5n₁ + 6n₂. Since this equals the quantity of the first nutrient which is 31,510, then  5n₁ + 6n₂ = 31,510 (2).

So, we have two simultaneous equations which we would solve to find the populations of A and B which satisfy both equations.

2n₁ + n₂ = 10,560  (1)

5n₁ + 6n₂ = 31,510 (2)

From (1) n₂ = 10,560 - 2n₁ (3)

Substituting equation (3) into (2), we have

5n₁ + 6(10,560 - 2n₁) = 31,510

expanding the brackets, we have

5n₁ + 63,360 - 12n₁ = 31,510

collecting like terms, we have

5n₁ - 12n₁ = 31,510 - 63,360

simplifying, we have

- 7n₁ = -31,850

dividing both sides by -7, we have

n₁ = -31,850/-7

n₁ = 4,550

Substituting n₁ = 4,550 into (3), we have

n₂ = 10,560 - 2(4,550)

n₂ = 10,560 - 9,100

n₂ = 1,460

So, we require 4,550 of species A and 1,460 of species B that can coexist in the environment so that all the nutrients are consumed each day

3 0
2 years ago
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