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Dahasolnce [82]
2 years ago
11

13. The table shows the height of a plant as it grows. Which equation in point-slope form gives the

Mathematics
1 answer:
maria [59]2 years ago
7 0

Given:

Table of values.

To find:

The equation in point slope form.

Solution:

From the given table it is clear that, the relationship is linear because the rate of change is constant because if x-value increases by 2 then y-values increases by 16.

Consider any two points from the table, i.e., (2,16) and (4,32).

Slope=\dfrac{y_2-y_1}{x_2-x_1}

Slope=\dfrac{32-16}{4-2}

Slope=\dfrac{16}{2}

Slope=8

The point is (2,16) and the slope is 8, so the point slope form is

y-y_1=m(x-x_1)

y-16=8(x-2)

Therefore, the relationship is linear and point slope form is y-16=8(x-2).

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If the third term in an arithmetic sequence is 7 and the common difference is -5, what is the value of the fourth termA.12B.2C.-
frozen [14]
The answer is 2 because the d/f is -5 so the term is bigger than 7
4 0
3 years ago
Suppose △PKN≅△BGH△PKN≅△BGH. Which other congruency statements are correct? Select each correct answer. △NKP≅△HBG△NKP≅△HBG △KPN≅△
NeTakaya

Answer:

△NPK≅△HBG; and △KNP≅△GHB

Explanation:

Using the given congruence statement, we can determine corresponding pieces of the triangles:

P corresponds to B; K corresponds to G; and N corresponds to H.

This means that △NKP≅△HGB, not HBG.

△KPN≅△GBH, not BHG.

△NPK≅△HBG; this is correct.

△KNP≅△GHB; this is correct.

8 0
2 years ago
What is the asymptote of the graph of f(x)=5x−1?
Marina86 [1]

The asymptotes of the graph of f(x) = \frac{5}{x - 1} are as follows:

  • Vertical: x = 1.
  • Horizontal: y = 0.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

f(x) = \frac{5}{x - 1}

For the vertical asymptote, we have that:

x - 1 = 0 \rightarrow x = 1.

For the horizontal asymptote, we have that:

y = \lim_{x \rightarrow \infty} f(x) = \frac{5}{\infty - 1} = 0.

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

3 0
1 year ago
Evaluate the limit. Shown above
Maksim231197 [3]

\displaystyle\lim_{n\to\infty}\frac{6n^2+5}{3n^2}=\lim_{n\to\infty}2+\dfrac5{3n^2}

As n\to\infty, the \dfrac5{3n^2} term will converge to 0, so the limit is 2 (B).

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3 years ago
3. John wants to open a showroom. He borrows
gavmur [86]

Answer:

2 i think

Step-by-step explanation:

5 0
2 years ago
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