Given:
Table of values.
To find:
The equation in point slope form.
Solution:
From the given table it is clear that, the relationship is linear because the rate of change is constant because if x-value increases by 2 then y-values increases by 16.
Consider any two points from the table, i.e., (2,16) and (4,32).
![Slope=\dfrac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=Slope%3D%5Cdfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
![Slope=\dfrac{32-16}{4-2}](https://tex.z-dn.net/?f=Slope%3D%5Cdfrac%7B32-16%7D%7B4-2%7D)
![Slope=\dfrac{16}{2}](https://tex.z-dn.net/?f=Slope%3D%5Cdfrac%7B16%7D%7B2%7D)
![Slope=8](https://tex.z-dn.net/?f=Slope%3D8)
The point is (2,16) and the slope is 8, so the point slope form is
![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29)
![y-16=8(x-2)](https://tex.z-dn.net/?f=y-16%3D8%28x-2%29)
Therefore, the relationship is linear and point slope form is
.