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VLD [36.1K]
3 years ago
6

PLZZZ HELP WILL MARK BRAINLIEST!!!!!!!!!!!!!

Mathematics
1 answer:
svp [43]3 years ago
3 0

Answer:

they want you to put the change in savings account on the y axis which is |

and they want you to put beginning balance on the x axis which is _ for example instead looking at it like 5,3 look at it like 3,5

Step-by-step explanation:

boom boom bang

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The slope of the graph of the y=2x-2 is 2. What is the y-intercept?
oee [108]
The y-intercept is located at -2. In the formula y=mx+b, b is the y intercept.

3 0
4 years ago
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2xГ3+7x<br> ________<br> Г6x
densk [106]

the answer is 1x

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7 0
3 years ago
Please help me please please help please in the picture please I need help
Ede4ka [16]

Answer:

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Step-by-step explanation:

6 0
3 years ago
A man and a woman agree to meet at a cafe about noon. If the man arrives at a time uniformly distributed between 11:40 and 12:10
kompoz [17]

Answer:

0.3888

Step-by-step explanation:

To solve the exercise we need a neutral time, so we define at 12:00 as time 0.

If the man arrives in a uniformly distributed time between 11:40 and 12:10, the time is distributed from -20 to 10.

If the woman arrives in a time evenly distributed between 11:45 and 12:20, the time is distributed from -15 to 20.

Assuming that each one arrives at 12: X and 12: Y for men and women, then the space of our time is defined as

Man [-20,10]

Woman [-15,20]

So,

f_x(x)=\frac{1}{10-(-20)}=\frac{1}{30}\\f_y(y)=\frac{1}{20-(-15)}=\frac{1}{35}

Then,

f_{xy}(x,y)=f_x(x)f_y(y)=\frac{1}{30} \frac{1}{35} = \frac{1}{1050}

The probability of finding an arrival less than 5 minutes is

P(|X-Y|\leq 5) = \int\limit^20_{-15} \int\limit^{x+5}_{x-5} f(x,y)dydx

P(|X-Y|\leq 5)= \frac{1}{1050}\int\limit^{20}_{-15} y|^{x+5}_{x-5}dx

P(|X-Y|\leq 5)= \frac{35*10}{900}=0.3888

6 0
3 years ago
I need help fr!! ignore the writing lol
Romashka [77]

Answer:

-40

Step-by-step explanation:

(-7)(5)-5=-35-5=-40

8 0
2 years ago
Read 2 more answers
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