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Archy [21]
3 years ago
8

As part of quality control, a pharmaceutical company tests a sample of manufacturer pills to see the amount of active drug they

contain is consistent with the labelled amount. That is, they are interested in testing the following hypotheses:
H0:μ=100H0:μ=100 mg (the mean levels are as labelled)

H1:μ≠100H1:μ≠100 mg (the mean levels are not as labelled)

Assume that the population standard deviation of drug levels is 55 mg. For testing, they take a sample of 1010 pills randomly from the manufacturing lines and would like to use a significance level of α=0.05α=0.05.

They find that the sample mean is 104104 mg. Calculate the zz statistic.

−17.89−17.89

−8.00−8.00

−5.66−5.66

−2.53−2.53

−0.80−0.80

0.800.80

2.532.53

5.665.66

8.008.00

17.8917.89
Mathematics
1 answer:
ryzh [129]3 years ago
8 0

Answer:

The z statistic is 0.23.

Step-by-step explanation:

Test statistic (z) = (sample mean - population mean) ÷ sd/√n

sample mean = 104 mg

population mean (mu) = 100 mg

sd = 55 mg

n = 10

z = (104 - 100) ÷ 55/√10 = 4 ÷ 17.393 = 0.23

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5 0
3 years ago
A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class
KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

<u><em /></u>

<u><em>Let p = percentage of seniors who skip their classes.</em></u>

So, Null Hypothesis, H_0 : p \leq 2%   {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, H_A : p > 2%   {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                   T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of seniors who skipped their classes = \frac{77}{2521}

           n = sample of classes = 2521

So, <u><em>test statistics</em></u>  =  \frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }

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Therefore, we conclude that seniors skip more than 2% of their classes.

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4 years ago
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5 0
3 years ago
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3 0
3 years ago
The population of a type of local dragonfly can be found using an infinite geometric series where a1 = 65 and the common ratio i
hram777 [196]
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S∞ = 78


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3 years ago
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