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WITCHER [35]
3 years ago
8

HELP 20 POINTS ASAP IM FAILING MATH IM GONNA CRY SNJSJSJSNSN PLEASE ANSWER ALL THREE QUESTIONS

Mathematics
1 answer:
Amanda [17]3 years ago
4 0
Lol, you said 20 points but that’s only 12 but sorry I’m also failing in math☹️☹️☹️ so i don’t really know the answer
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Keith bought a desktop computer and a laptop computer. Before finance charges, the laptop cost $150 more than the desktop. He pa
ss7ja [257]

Answer: desktop = $1750, laptop = $1900

<u>Step-by-step explanation:</u>

Let x represent the cost of the desktop

then x + 150 is the cost of the laptop.

.07x + .055(x + 150) = 227

.07x + .055x + 8.25 = 227

.125x = 218.75

x = 1750

desktop (x) = $1750

laptop (x + 150) = $1750 + $150 = $1900

5 0
3 years ago
What is the slope of the line? please help right answers only please!
grigory [225]

Answer: 2

Step-by-step explanation:

Slope = \frac{y_{2} -y_{1} }{x_{2}-x_{1}  } \\Slope = \frac{3 - 1}{1}  = 2

8 0
3 years ago
Read 2 more answers
All of the points in the picture are on the same line *help asap*
KengaRu [80]

Answer:

yes all of the points are on the same line

Step-by-step explanation:

4 0
3 years ago
A coin is tossed 13 times.
Serga [27]

Answer:

a) 2¹³

b)  0.0873

c) 0.9983

d) 0.9538

Step-by-step explanation:

a) How many different outcomes are possible?

For every toss, there are two possible outcomes (heads or tails), so if we toss the coin 13 times the total of outcomes possible is 2¹³

b)  What is the probability of getting exactly 4 heads?

The definition of probability is an event is: number of favourable events/ number of total events.

When we have two possible outcomes p, q and we repeat the experiment multiple times, we apply the Binomial distribution, in this distribution the probability of getting exactly k successes in n trials is given by

P(X=k) =nCk (p^{k} )(1-p)^{n-k} where p represents the probability of success. nCk refers to the combinations of k elements out of n elements.

So we have to know how many different ways we can get exactly 4 heads.

let's name p = probability of getting heads = 0.5

1 -p = probability of getting tails = 0.5

We are going to toss the coin 13 different times and we want to get heads 4 times and tails 9 times.

So, by the Binomial Distribution we would have:

P(X=4) = 13C4 (0.5)⁴(0.5)⁹ = 715 (0.5)¹³ = 0.0873

Thus, the probability of getting exactly 4 heads is 0.0873.

c)  What is the probability of getting at least 2 heads?

We are going to use the same binomial distribution but now we need at least to heads, this can be written as <u>1 - (P(X=0) + P(X=1))</u>

P(X=0) + P(X=1) = 13C0 (0.5)⁰(0.5)¹³ + 13C1 (0.5)¹(0.5)¹² = 0.0001220703125 + 0.0015869140625 = 0.001708984375

1 - 0.001708984375 = 0.998291015625

The probability of getting at least 2 heads is 0.9983

d) What is the probability of getting at most 9 heads?

We are going to use the same binomial distribution but now we need at most 9 heads. This can be written as <u>1 - (P(X=10) + P(X = 11) + P(X=12) + P(X=13))</u>

1 - (P(X=10) + P(X = 11) + P(X=12) + P(X=13)) =1 -(13C10(0.5)¹⁰(0.5)³ + 13C11(0.5)¹¹(0.5)²+ 13C12(0.5)¹²(0.5)¹ + 13C13(0.5)¹³(0.5)⁰) = 0.95385742188

The probability of getting at most 9 heads is 0.9538

6 0
3 years ago
I need help Estimate 81/4 but into a number
kondaur [170]
So do 81 divided by 4 we know that 80 divided by 4 is 20 so it would be 20 and some change
7 0
3 years ago
Read 2 more answers
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