Answer:
The common ratio is 5 and the 5th term is 1250
Step-by-step explanation:
The common ratio is given by
r=U(2)/U (1)
=10/2
=5
The fifth term
U (n)=ar^n-1
U(5)=2(5)^5-1
=2×5^4
=2×625
=1250
Given :
C, D, and E are col-linear, CE = 15.8 centimetres, and DE= 3.5 centimetres.
To Find :
Two possible lengths for CD.
Solution :
Their are two cases :
1)
When D is in between C and E .
. . .
C D E
Here, CD = CE - DE
CD = 15.8 - 3.5 cm
CD = 12.3 cm
2)
When E is in between D and C.
. . .
D E C
Here, CD = CE + DE
CD = 15.8 + 3.5 cm
CD = 19.3 cm
Hence, this is the required solution.
9x^2-16y^2=
(3x+4y)(3x-4y)
Y=(x-4)/2x-11x+28
y=(x/2x)-(4/2x)-11x+28
y=0.5x-2x-11x-28
1. subtract like terms
2. add 28 on both sides
3. so on and so forth...