All categories

3 years ago

Find the solution of this system of equations.

Mathematics

1 answer:

Tems11 [23]3 years ago

3 0

Answer: $x=-21, y=-33$

$x-y=12,\\18x-12y=18 ( divide by 6)\\3x-2y=3, 2nd Eq.\\multiply- first -equation by 2\\\\2x-2y=24, 1st Eq.\\subtract-the- second -equation- from -first\\2x-3x=24-3,\\-x=21 or x=-21,\\\\substitute-the-value-of -x\\-21-y=12,\\y=-21-12= -33\\$

Step-by-step explanation:

You might be interested in

Mia has two more than three times the number of model cars that Orville has. If Orville has c model cars, Which algebraic expres

Ahat [919]

Answer:

3c+2 is the correct answer

3 0

3 years ago

HELP ,<br> simplify a^3 a^10

Dominik [7]

A^13. Your welcome. :))

3 0

3 years ago

Expand<br> (2x - 3)4 <br><br> Can you help me expand this by using the binomial theorem?

saw5 [17]

The value of expanding (2x -3)^4 is 16x^4 + 96x^3 +216x^2 -216x + 81

<h3>How to expand the expression?</h3>

The expression is given as:

(2x -3)^4

Using the binomial expansion, we have:

$(2x -3)^4 = ^4C_0 * (2x)^4 * (-3)^0 +^4C_1 * (2x)^3 * (-3)^1 + ^4C_2 * (2x)^2 * (-3)^2 + ^4C_3 * (2x)^1 * (-3)^3 + ^4C_4 * (2x)^0 * (-3)^4$

Evaluate the combination factors.

So, we have:

$(2x -3)^4 = 1 * (2x)^4 * (-3)^0 + 4 * (2x)^3 * (-3)^1 + 6 * (2x)^2 * (-3)^2 + 4 * (2x)^1 * (-3)^3 + 1 * (2x)^0 * (-3)^4$

Evaluate the exponents and the products

$(2x -3)^4 = 16x^4 + 96x^3 +216x^2 -216x + 81$

Hence, the value of expanding (2x -3)^4 is 16x^4 + 96x^3 +216x^2 -216x + 81

Read more about binomial expansions at:

brainly.com/question/13602562

#SPJ1

8 0

2 years ago

Translate the given phrase into an algebraic expression and simplify if possible: the difference of −5 and −30.

lawyer [7]

Answer:

IIaI-IbII

Step-by-step explanation:

II-30I-I-5II=

I30-5I=

I25I=

II-5I-I-30II=

I5-30I=

I-25I=

8 0

2 years ago

Can all edges have the same length? Yes or No

DedPeter [7]

Yes they can all have the same

7 0

3 years ago

Read 2 more answers