The college that Dora attends is selling tickets to the annual
1 answer:
Answer:
The solution of the system of equations is (11, 12)
Step-by-step explanation:
∵ The price of each student ticket is $x
∵ The price of each adult ticket is $y
∵ They sold 3 student tickets and 3 adult tickets for a total of $69
∴ 3x + 3y = 69 ⇒ (1)
∵ they sold 5 student tickets and 3 adults tickets for a total of $91
∴ 5x + 3y = 91 ⇒ (2)
Let us solve the system of equations using the elimination method
→ Subtract equation (1) from equation (2)
∵ (5x - 3x) + (3y - 3y) = (91 - 69)
∴ 2x + 0 = 22
∴ 2x = 22
→ Divide both sides by 2 to find x
∵
∴ x = 11
→ Substitute the value of x in equation (1) or (2) to find y
∵ 3(11) + 3y = 69
∴ 33 + 3y = 69
→ Subtract 33 from both sides
∵ 33 - 33 + 3y = 69 - 33
∴ 3y = 36
→ Divide both sides by 3
∵
∴ y = 12
∴ The solution of the system of equations is (11, 12)
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Answer:
Senn needs to give Ms. Lady 4.6 minutes head start
Senn needs to give Ms. Beetle 18.4 minutes head start
The equation for each bug are;
For Senn, the equation for the experiment is 5 × t₁ = 92 feet
For Ms. Lady, the equation for the experiment is 4 × (t₁ + 4.6) = 92 feet
For Ms. Beetle , the equation for the experiment is 4 × (t₁ + 18.4) = 92 feet
Please find attached the required graph and table of values
Step-by-step explanation:
The given parameters are;
The average crawling time of Ms. Lady = 4 feet per minute
The average crawling time of Ms. Beetle = 2.5 feet per minute
The average crawling time of Senn = 5 feet per minute
The distance to the rose bush = 92 feet
Therefore, we have;
The time, t, duration for Senn to arrive at the Rose bush is given by the following relation,
Time, t = Distance, d/(Speed, s)
Given that the speed of the bugs is equal to their average crawling time, we have
For Senn
Time, t = 92/(5 ft/Min) = 18.4 minutes
For, Ms. Lady
Time, t = 92/(4 ft/Min) = 23 minutes
For, Ms. Beetle
t = 92/(2.5 ft/Min) = 36.8 minutes
Therefore;
Senn needs to give Ms. Lady 23 - 18.4 = 4.6 minutes head start
Similarly, Senn needs to give Ms. Beetle 36.8 - 18.4 = 18.4 minutes head start
The equation for each bug are therefore;
For Senn, the equation for the experiment is given as follows ;
5 × t₁ = 92 feet
For Ms. Lady, the equation for the experiment is given as follows;
4 × (t₁ + 4.6) = 92 feet
For Ms. Beetle , the equation for the experiment is given as follows;
4 × (t₁ + 18.4) = 92 feet.
