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2 years ago

A concert is attended by2500 people.If 47% are adult females and 32% are adults males,how many children attended?

Mathematics

2 answers:

Anastaziya [24]2 years ago

7 0

Answer:

use division

Step-by-step explanation:

irina [24]2 years ago

6 0

Answer:

525

Step-by-step explanation:

first we need to work out the percentage of the children who attended to to do this we need to add 47% with 32% which is 79%. Then you need to take away 79% from 100% which is 21%. After that you now know that 21% is the children who attended but you wanted to know how many children so to work this out you would find 21% of 2500 which would give you 525.

i hope this helps

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dalvyx [7]

Answer:

Step-by-step explanation:

Actually Welcome to the Concept of the linear equations..

Here given value of x= 5 and y =1 , so we get as,

5a + b = 38 and 5b - a = 8

so, now we multiply equation no. 2 by 5 all over.

==> 25b - 5a = 40....(1)

hence adding new equation and equation no. 1

26b = 78

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2 years ago

On a map, 1/4 inch between locations represents an actual distance of 2 miles between the locations. What is the actual distance

Fittoniya [83]

Answer:

12/17 miles

Step-by-step explanation:

Make the denominators equal -> 1/4 = 17/68, 3/34 = 6/68

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The ratio between 17/68 and 6/68 is 17/68 : 6/68 = 17/6
So, the ratio between the distance should also be 17/6

-> 3/34 inches represent 2 : 17/6 = 12/17 (miles)

Hope it helps :)

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2 years ago

What is 0.05 divided by 4.8 ?

postnew [5]

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3 years ago

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Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-

ivanzaharov [21]

Answer:

$c = \displaystyle\frac{9}{4}$

Step-by-step explanation:

The following information is missing in the given question:

$f(x) = \sqrt{x}$

Using this we may solve the question as:

We are given the following in the question:

$f(x) = \sqrt{x}, x \in [0,9]$

We have to find the number c such that f(x) satisfies the Mean value theorem.

Mean Value theorem:

It states that if the function is differentiable in the closed interval [a,b], differentiable in the interval (a,b), then there exist c in (a,b) such that:

$f'(c) = \displaystyle\frac{f(b)-f(a)}{b-a}$

Now,

$f(x) = \sqrt{x}\\f'(x) = \frac{1}{2\sqrt{x}}$

Continuity in [0,9]

Since a polynomial function is continuous everywhere, f(x) is continuous in [0,9]

Differentiability in (0,9)

Since a polynomial function is differentiable everywhere the given function is differentiable in interval (0,9)

Then, by mean value theorem:

$f'(c) = \displaystyle\frac{f(b)-f(a)}{b-a}\\\\\frac{1}{2\sqrt{c}} = \frac{f(9) - f(0)}{9-0} = \frac{3}{9}\\\\\frac{1}{2\sqrt{c}} = \frac{1}{3}\\\\c= \frac{9}{4}$

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2 years ago

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Answer:

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Step-by-step explanation:

You would move the decimal over 3 times to the left from the end of 9000

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3 years ago

A concert is attended by2500 people.If 47% are adult females and 32% are adults males,how many children attended?​

A concert is attended by2500 people.If 47% are adult females and 32% are adults males,how many children attended?