An algebraic expression is an expression built up from integer constants, variables, and the algebraic operations.
The 1st one
Well it's the same as normal exponents so you multiply 2/3 x 2/3 x 2/3 x 2/3 x 2/3
Answer: " m = zC / (C − z) " .
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Explanation:
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Given: 1/C + 1/m = 1/z ; Solve for "m".
Subtract "1/C" from each side of the equation:
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1/C + 1/m − 1/C = 1/z − 1/C ;
to get: 1/m = 1/z − 1/C ;
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Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
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mzC {1/m = 1/z − 1/C} ;
to get: zC = mC − mz ;
Factor out an "m" on the "right-hand side" of the equation:
zC = m(C − z) ; Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;
zC / (C − z) = m(C − z) / m ; to get: 24/8 = 3 24
zC/ (C − z) = m ; ↔ m = zC/ (C − z) .
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When solving the equation, you first have h- 9/5. So it would by x=(h - 9/5). But you are not done yet. you still have to divide it by R to get x. So the final equation is x=(h - 9/5) ÷ R
