Question

FIRST TO ANSWER GETS BRAINLIEST!

Answer 1

Answer:

$\huge \boxed{ \red{ \boxed{c)78 \: units ^{2} }}}$

Step-by-step explanation:

to understand this

you need to know about:

• circle
• PEMDAS

tips and formulas:

• $\rm \:A_{shaded}= \dfrac{\theta}{360} \times \pi {r}^{2}$

let's solve:

1. $\sf sustitute \: the \: value \: of \: \theta \: and \: r : \\ A_{shaded} = \frac{140}{360} \times \pi \times {8}^{2}$
2. $\sf simpify \: squre : \\ A_{shaded} = \frac{140}{360} \times \pi \times 64$
3. $\sf simpify \: fraction: \\ A_{shaded} = \frac{7}{18} \times \pi \times 64$
4. $\sf reduce \: 64: \\ A_{shaded} = \frac{7}{ \cancel{ \: 18} \: ^{9} } \times \pi \times \cancel{ 64} \: ^{32} \\ A_{shaded} = \frac{7}{9} \times \pi \times 32\\ A_{shaded} = \frac{224\pi}{9}$

$\large A_{shaded}\approx 78 \: square \: units$

Answer 2

Answer:

area of shaded region =140/360 ×π×8²=78unit²

approx