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Troyanec [42]
3 years ago
6

Find the center and raduis of the circle

Mathematics
2 answers:
goldenfox [79]3 years ago
6 0

Answer:

C

Step-by-step explanation:

The circle equation (x-a)²+(y-b)²=r² has a radius of r and a center of (a,b).

You can expand your equation from (x-5)²+y²=9 to (x-5)²+(y-0)²=3².

Using this information, you can see that a=5, b=0, and r=3.

Therefore the center is (5,0) and the radius is 3.

**This question involves circle equations, which you may want to revise. I'm always happy to help!

posledela3 years ago
5 0

Answer:

B

Step-by-step explanation:

Because the equation can be written in the form (x-p)^2+(y-q)^2. So it represents a <u>circle</u> with the radius r=3 and the center of (5,0).

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Georgie spent 15 hours doing her chores last week. This week
Oksana_A [137]

Answer:

Yes. Explanation: 120%=1.2. If Maxine is correct, then she spent 1.2 times the hours she did homework than last week. 15⋅1.2=18.0=18.

Yes Explanation: 120

3 0
3 years ago
PLEASE HELP!!! I WILL GIVE BRAINY!!!
11111nata11111 [884]
The first one is 4/3

We can solve by,

{x}^{2} \times 180 = 320

x = \frac{4}{3}

{ \frac{4}{3} }^{2} \times 180 = 320 = true

~~

The second one is 35.

Idk how to explain...

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The third one is a 6 - gon therefore cannot be C or D.

I'd say the third one is A., it looks like it's caving in.
4 0
2 years ago
Read 2 more answers
What must be true for lines a and b to be parallel lines? Check all that apply
iren [92.7K]

the question does not present the options, but this does not interfere with the resolution


we know that

if a and b are parallel lines

so


1) m∠2=58°------> by corresponding angles


2) m∠1=4x-10------> by alternate exterior angles


3) [m∠2+m∠(3x-1)]+m ∠1=180°------> by supplementary angles

58+(3x-1)+4x-10=180

7x=180-47

7x=133

x=19°


4) angle (4x-10)=-4*19-10-------> 66°


5) angle 3x-1=3*19-1-------> 56°

3 0
3 years ago
For the given polynomials find the sum of the squares of the roots. P(x)=x^3-x^2-18x+k
slega [8]

\text{Given that,}\\\\P(x) = x^3 -x^2 -18x+k\\\\\text{If the roots are}~ \alpha, ~ \beta,~\text{and}~ \gamma, ~ \text{then},\\\\\alpha +\beta+\gamma= -\dfrac{(-1)}1 = 1\\\\\alpha \beta +\beta \gamma + \gamma \alpha= -\dfrac{18}1 = -18\\ \\\text{Now, sum of the  squares of the roots,}\\\\\alpha^2 + \beta^2 + \gamma^2 = ( \alpha + \beta + \gamma)^2 -2(\alpha \beta + \gamma \beta + \gamma \alpha)\\ \\~~~~~~~~~~~~~~~~~~=1^2 - 2(-18)\\\\~~~~~~~~~~~~~~~~~~=1+36\\\\~~~~~~~~~~~~~~~~~~=37

6 0
2 years ago
4^2•2^-3 =<br> 2<br> 1/2<br> -128
Kitty [74]
The answer is 2 because you multiply them both
3 0
3 years ago
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