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givi [52]
3 years ago
5

A right triangular prism and its net are shown below.

Mathematics
2 answers:
Law Incorporation [45]3 years ago
6 0

Answer:

A=2

B=12

C=5

D=13

SA=411mm

Step-by-step explanation:

SA=bh+(s1+s2+s3)H

=12×5+(12+2+13)(13)

Viefleur [7K]3 years ago
4 0
It’s 1333333333!!!!!!
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Find the geometric proof
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Answer:

See Explanation

Step-by-step explanation:

Line l is bisector of MO... (given)

\therefore MN = NO.... (1)

\because MN + NO = MO..(M-N-O)

\therefore NO + NO = MO..[From \:(1)]

\therefore 2NO = MO

\therefore NO = \frac{1}{2} MO

\therefore NO = \frac{1}{2}\times 24..(\because MO=24)

\therefore NO =12

Thus Proved

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A business owner collected data on the people working for her company. She determined the average number of minutes each employe
Naddika [18.5K]

Answer:

The comparison using median and IQR is best because one of the graphs is not symmetrical.<em> </em>

Step-by-step explanation:

The following information is missing

<em>A box plot titled Number of Minutes Women Spend on Breaks. The number line goes from 30 to 70. The whiskers range from 30 to 54, and the box ranges from 34 to 50. A line divides the box at 48.  </em>

<em>A box plot titled Number of Minutes Men Spend on Breaks. The number line goes from 30 to 70. The whiskers range from 30 to 68, and the box ranges from 36 to 60. A line divides the box at 48.  </em>

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<em>The comparison would be more accurate using the mean and MAD because one of the graphs is symmetric. </em>

<em>The comparison would be more accurate using the mean and MAD because the median of both data sets is the same. </em>

<em>The comparison using median and IQR is best because one of the graphs is not symmetrical. </em>

<em>The comparison using median and IQR is best because the median is greater than the IQR for both data sets.</em>

<em />

Mean and MAD are useful for comparison when both data sets are symmetrical.

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