Answer:
Example:
A bag contains 3 black balls and 5 white balls. Paul picks a ball at random from the bag and replaces it back in the bag. He mixes the balls in the bag and then picks another ball at random from the bag.
a) Construct a probability tree of the problem.
b) Calculate the probability that Paul picks:
i) two black balls
ii) a black ball in his second draw
Solution:
tree diagram
a) Check that the probabilities in the last column add up to 1.
b) i) To find the probability of getting two black balls, first locate the B branch and then follow the second B branch. Since these are independent events we can multiply the probability of each branch.
ii) There are two outcomes where the second ball can be black.
Either (B, B) or (W, B)
From the probability tree diagram, we get:
P(second ball black)
= P(B, B) or P(W, B)
= P(B, B) + P(W, B)
Answer: OPTION B.
Step-by-step explanation:
Given the equation 
you can find an equivalent equation by simplifying it.
You need to remember the multiplication of signs:
Now you can apply the Distributive property:
Simplifying the equation, you get:
You can observe that this equivalent equation matches with the equation provided in option B.
Answer:
Answer:(15,65) (30,60)(45,55)
Step-by-step explanation:
Sorry for that kid that did not answer
Answer:
32.5
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