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stepladder [879]
3 years ago
6

Find the equation of the line for the following table:

Mathematics
1 answer:
Maru [420]3 years ago
6 0
-5 maybe





Let me know if I am wrong have a good day
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Show work please :)
fgiga [73]

Answer:

60

Step-by-step explanation:

90/100 = 54

Cross multiplying:

100 * 54 / 90

5400/90

60

4 0
2 years ago
Variable p is 2 more than variable d. Variable p is also 1 less than variable d. Which pair of equations best models the relatio
goldenfox [79]
If you would like to find a pair of equations that best models the relationship between p and d, you can do this using the following steps:

p is 2 more than d ... p = d + 2
p is 1 less than d ... p = d - 1

The correct result would be p = d + 2 and <span>p = d - 1.</span>
4 0
3 years ago
Read 2 more answers
What is the answer for y? 2(y+2)​
Maksim231197 [3]

Answer:

2y + 4

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
If f(x) = x2 + 2x + 3, what is the average rate of change of Rx) over the interval (-4, 6]?
JulijaS [17]

Answer:

Step-by-step explanation:

The average rate of change of a function over an interval is simply the slope over the interval because:

let \: g(x)=f'(x)\\\frac{\int\limits^b_a {g(x)} \, dx }{b-a}(the\:average\:value\:of\:g)=\frac{f(b)-f(a)}{b-a}

We have to know f(6) and f(-4)

f(x) = x^2 + 2x + 3\\f(6) = 6^2 + 2(6) + 3\\f(6) = 36 + 12 + 3\\f(6) = 51\\\\f(-4) = (-4)^2 + 2(-4) + 3\\f(-4) = 16 - 8 + 3\\f(-4) = 11\\\\\frac{f(6)-f(-4)}{6-(-4)} = \frac{51-11}{10} = \frac{40}{10} = 4

3 0
3 years ago
Helppp please show work
Mamont248 [21]

Step-by-step explanation:

<u>Given</u><u> </u><u>that</u><u>:</u><u>-</u>

  • Side AC measures 6 units
  • Side BC measures 9.5 units
  • Side AB measures 11 units

<u>To</u><u> </u><u>find</u><u>:</u><u>-</u>

  • The cosB as a decimal rounded to the nearest hundredth

<u>We</u><u> </u><u>know</u><u> </u><u>that</u><u>, </u>

{ \bigstar \: { \underline{ \boxed{ \cos( \theta ) \:  =  \sf\frac{adjecent \: side}{hypotenuse}  }}}}

<u>Solution</u><u>:</u>

\longrightarrow \rm  \cos(B)  =  \dfrac{BC}{AB}

\longrightarrow \rm  \cos(B)  =  \dfrac{9.5}{11}

\longrightarrow \rm  \cos(B)  =  \dfrac{95}{110}

\longrightarrow \rm  \cos(B)  =  0.8 63

\longrightarrow  \rm  \cos(B)   \approx \: 0.9

<u>Therefore:</u>

  • Cos B equals 0.9

6 0
2 years ago
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