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For a relation to be a function it must be 
relation is not a function.
In the above options, C is relation therefore cannot be a function.
The reason is that 3 alone maps onto -2 and 5, in the ordered pairs (3,-2) and (3,5). This disqualifies it from being a function.
Hence the graph of this relation will not pass the vertical line test
In the above options, C is
The reason is that 3 alone maps onto -2 and 5, in the ordered pairs (3,-2) and (3,5). This disqualifies it from being a function.
Hence the graph of this relation will not pass the vertical line test
Answer:
Step-by-step explanation:
Ok, so we start by setting the integral up. The integral we need to solve is:
so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:
U=5+x
du=dx
x=U-5
so when substituting the integral will look like this:
now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:
so we must define p, q, p' and q':
p=ln U
q'=U-5
and now we plug these into the formula:
Which simplifies to:
Which solves to:
so we can substitute U back, so we get:
and now we can simplify:
notice how all the constants were combined into one big constant C.