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Ber [7]
3 years ago
12

What is -10 + (-3/4)​

Mathematics
1 answer:
Anna35 [415]3 years ago
3 0

Answer:

-43/4

Step-by-step explanation:

-10+(-3/4)

-10-3/4

-43/4

demical form: -10.75

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If 0 is an angle in standard position and its terminal side passes
Gre4nikov [31]

Answer:-27/7

Step-by-step explanation:

3 0
3 years ago
ted popped a baseball straight up with an initial velocity of 48 ft/s. The height, h, in feet, of the ball above the ground is m
creativ13 [48]

Answer:

3 seconds

Step-by-step explanation:

We have to give us the following function h (t) = - 16 * t ^ 2 + 48 * t + 3

Now, they tell us that the height is 3 feet, therefore replacing that value we have left:

3 = -16 * t ^ 2 + 48 * t + 3, operating cancels 3. And it would be:

-16 * t ^ 2 + 48 * t = 0

Removing common factor -16 * t, it would be:

(-16 * t) * (t - 3) = 0

We have two solutions:

-16 * t = 0 ---> t = 0

 t - 3 = 0 ---> t = 3

Because the time cannot be 0 seconds, the time it would take the ball in the air is 3 seconds.

4 0
3 years ago
Heya!
nataly862011 [7]

Answer:

m\angle QSN=65^\circ

Step-by-step explanation:

In the given figure, PQRS is a rhombus and SRM is an equilateral triangle.

We are also given that SN⊥RM and that ∠PRS = 55°.

And we want to find the measure of ∠QSN.

Remember that since PQRS is a rhombus, the angles formed by its diagonals are right angles. Let the intersection point of the diagonals be K. Therefore:

m\angle RKS=90^\circ

Now, RKS is also a triangle. The interior angles of all triangles must be 180. Thus:

m\angle RKS+m\angle KSR+m\angle SRK=180

Substitute in known values:

90+55+m\angle KSR=180

Solve for ∠KSR:

m\angle KSR+145=180\Rightarrow m\angle KSR=35^\circ

Since SRM is an equilateral triangle, this means that:

m\angle SRM=m\angle RMS=m\angle MSR=60^\circ

Note that RNS is also a triangle. Therefore:

m\angle SRM+m\angle RNS+m\angle NSR=180

Substitute in known values:

60+90+m\angle NSR=180

So:

m\angle NSR+150=180\Rightarrow m\angle NSR=30^\circ

∠QSN is the addition of the two angles:

m\angle QSN=m\angle KSR+m\angle NSR

Therefore:

m\angle QSN=35+30=65^\circ

4 0
3 years ago
Read 2 more answers
Which expressions are equivalent to 5+ (-3)(6x – 5)?
Viefleur [7K]

Hello

5 + ( -3) ( 6x - 5 )

= 5 - 3*6x + 5*3

= -18x + 20

Good day. ;)

4 0
3 years ago
Read 2 more answers
*respond AsAp*
charle [14.2K]
There are couple ways to go about this. If the polynomial is odd the graph with be symmetric to the origin, and if the polynomial even the graph with be symmetric to the y-axis. An odd degree polynomial end points with go in opposite directions, even degree polynomial end points will go in the same direction. A positive even degree poly will open up(smile), a negative even degree poly will open down (frowny face). I can go on if needed, I hope this helps :)
4 0
4 years ago
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