Answer:-27/7
Step-by-step explanation:
Answer:
3 seconds
Step-by-step explanation:
We have to give us the following function h (t) = - 16 * t ^ 2 + 48 * t + 3
Now, they tell us that the height is 3 feet, therefore replacing that value we have left:
3 = -16 * t ^ 2 + 48 * t + 3, operating cancels 3. And it would be:
-16 * t ^ 2 + 48 * t = 0
Removing common factor -16 * t, it would be:
(-16 * t) * (t - 3) = 0
We have two solutions:
-16 * t = 0 ---> t = 0
t - 3 = 0 ---> t = 3
Because the time cannot be 0 seconds, the time it would take the ball in the air is 3 seconds.
Answer:
Step-by-step explanation:
In the given figure, PQRS is a rhombus and SRM is an equilateral triangle.
We are also given that SN⊥RM and that ∠PRS = 55°.
And we want to find the measure of ∠QSN.
Remember that since PQRS is a rhombus, the angles formed by its diagonals are right angles. Let the intersection point of the diagonals be K. Therefore:
Now, RKS is also a triangle. The interior angles of all triangles must be 180. Thus:
Substitute in known values:
Solve for ∠KSR:
Since SRM is an equilateral triangle, this means that:
Note that RNS is also a triangle. Therefore:
Substitute in known values:
So:
∠QSN is the addition of the two angles:
Therefore:
There are couple ways to go about this. If the polynomial is odd the graph with be symmetric to the origin, and if the polynomial even the graph with be symmetric to the y-axis. An odd degree polynomial end points with go in opposite directions, even degree polynomial end points will go in the same direction. A positive even degree poly will open up(smile), a negative even degree poly will open down (frowny face). I can go on if needed, I hope this helps :)
