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Kisachek [45]
3 years ago
9

The nth term of an AP is 12-4n. Find the first term and the common difference.

Mathematics
1 answer:
Virty [35]3 years ago
4 0

Answer:

the first term is 8 and common difference d is -4.

Step-by-step explanation:

We are given nth term of an arithmetic sequence is: aₙ=12-4n

We need to find first term and common difference of given arithmetic sequence

First term can be found by  putting n=1:

a_n=12-4n\\a_1=12-4(1)\\a_1=12-4\\a_1=8

So, first term is a₁= 8

Now to find common difference we need to find second term

Second term can be found by putting n=2

a_n=12-4n\\a_2=12-4(2)\\a_2=12-8\\a_2=4

So, second term is: 4

The common difference is found by subtracting second term with first term: a₂-a₁= 4-8 = -4

So, first term is 8 and common difference d is -4

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In ΔIJK, k = 57 inches, i = 37 inches and ∠J=141°. Find ∠I, to the nearest degree.
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Answer:

<I= 15degrees

Step-by-step explanation:

Using the cosine rule formulae;

j² = i²+k²-2i cos <J

j² = 37²+57² - 2(37)(57)cos <141

j² = 1369+ 3249- 4218cos <141

j² = 4618- 4218cos <141

j² = 4618-(-3,278)

j²= 7,896

j = √7,896

j = 88.86inches

Next is to get <I

i² = j²+k²-2jk cos <I

37² = 88.86²+57² - 2(88.86)(57)cos <I

1369 = 7,896.0996+ 3249- 10,130.04cos <I

1369 = 11,145.0996 - 10,130.04cos <I

1369 - 11,145.0996 = - 10,130.04cos <I

-9,776.0996=- 10,130.04cos <I

cos <I =9,776.0996 /10,130.04

cos<I = 0.96506

<I = 15.19

<I= 15degrees

8 0
3 years ago
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Answer:

1.4

Step-by-step explanation:

0.5f-2.3g where f=12 and g=2

substitute 12 in for f and 2 in for g and solve

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Step-by-step explanation:

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