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3 years ago

Which equation has infinitely many real solutions?

Mathematics

1 answer:

lina2011 [118]3 years ago

8 0

B. After distributing, each side will be exactly the same. This means there is infinite solutions.

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A popular brand of running

s2008m [1.1K]

$119 - $68 = $51

51/68 x 100 = .75

.75 x 100 = 75%

So, there was a 75% percent increase in the price.

7 0

2 years ago

Read 2 more answers

Find the value of X and give a reason for the relation ship between the angles.

Ostrovityanka [42]

Answer:

x = 55

Step-by-step explanation:

(x - 14) + 99 + 220 = 360

x - 14 + 99 + 220 = 360

x - 14 + 319 = 360

x + 305 = 360

x = 360 - 305

x = 55

-TheUnknownScientist

8 0

2 years ago

Solve 73 make sure to also define the limits in the parts a and b

Aleks04 [339]

73.

$f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}$

$\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3$ $\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3$

Since we can't divide by zero, we need to find when:

$x^4-2x^2+144=0$

But before, we can factor the numerator and the denominator:

$\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}$

Now, we can conclude that the vertical asymptotes are located at:

$\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}$

so, for x = -3:

$\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty$ $\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty$

For x = 4:

$\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$ $\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$

4 0

5 months ago

What is negative thirty divided by three

Phoenix [80]

Answer:

The answer is -10

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Help,again... ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍

coldgirl [10]