4 years ago

Which equation has infinitely many real solutions?

Mathematics

1 answer:

lina2011 [118]4 years ago

8 0

B. After distributing, each side will be exactly the same. This means there is infinite solutions.

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<img src="https://tex.z-dn.net/?f=f%28x%29%3D%203x%2B1%20%2C%20g%28x%29-%202x%20-1" id="TexFormula1" title="f(x)= 3x+1 , g(x)- 2

Bond [772]

Answer:

(fog)(x)=f(g(x))=2(3x+2)−1=6x+4−1=6x+3=3(2x+1)

8 0

3 years ago

Find the inequality represented by the graph

Irina18 [472]

Answer:

-4/3 Negative Downward slope

7 0

3 years ago

Find the term indecent of x in the expansion of (x^2-1/x)^6

Mars2501 [29]

By the binomial theorem,

$\displaystyle \left(x^2-\frac1x\right)^6 = \sum_{k=0}^6 \binom 6k (x^2)^{6-k} \left(-\frac1x\right)^k = \sum_{k=0}^6 \binom 6k (-1)^k x^{12-3k}$

I assume you meant to say "independent", not "indecent", meaning we're looking for the constant term in the expansion. This happens for k such that

12 - 3k = 0 ===> 3k = 12 ===> k = 4

which corresponds to the constant coefficient

$\dbinom 64 (-1)^4 = \dfrac{6!}{4!(6-4)!} = \boxed{15}$

3 0

3 years ago

22, 55, 99, 1414, _____, ____arithmetic, geometric, or neither.

mixer [17]

I believe it's neither. There is no common difference or ratio. They keep changing, it's not consistent.

6 0

4 years ago

Michelle and Michael collect baseball cards. Michael has 5 more cards then Michelle. Together they have 27 cards. How many cards

kap26 [50]

Michael is x. Michelle is y.
x+y=27
x-5=y

Substitute y
x+(x-5)= 27
2x-5=27
2x=32
x=16

Plug in x value
(16)+y=27
y=11

Final answer: Michael-16, Michelle-11

5 0

3 years ago

Read 2 more answers